Salt bridge A concentration cell similar to the one shown is composed of two Mn electrodes and solutions of different Mn2+ concentrations. The left compartment contains 1.41 M Mn²+, and the right compartment contains 1.33 M Mn²+. Calculate the cell potential for this reaction at 298 K. V In this manganese concentration cell, the reaction would proceed spontaneously to transfer Mn²+ Use standard reduction potentials to calculate the equilibrium constant for the reaction: Cd²+ (aq) + Pb(s) → Cd(s) + Pb²+ (aq) From the table of standard reduction potentials: Ca²+/Ca = -0.403 V, E Pb²+/Pb = -0.126 V Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.

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Chapter18: Electrochemistry
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Problem 18.50QE
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Chemistry
Salt bridge
A concentration cell similar to the one shown is composed of two Mn electrodes and
solutions of different Mn²+ concentrations. The left compartment contains 1.41 M
Mn²+, and the right compartment contains 1.33 M Mn²+.
Calculate the cell potential for this reaction at 298 K.
V
In this manganese concentration cell, the reaction would proceed spontaneously to
transfer Mn²+
Use standard reduction potentials to calculate the equilibrium constant for the reaction:
Cd²+ (aq) + Pb(s) → Cd(s) + Pb²+ (aq)
From the table of standard reduction potentials: E²+
= -0.403 V,
+/Cd
Epb²+
= -0.126 V
'Pb²+/Pb
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round
off error when taking the antilogarithm.
Equilibrium constant at 298 K:
AGO for this reaction would be
than zero.
Transcribed Image Text:Chemistry Salt bridge A concentration cell similar to the one shown is composed of two Mn electrodes and solutions of different Mn²+ concentrations. The left compartment contains 1.41 M Mn²+, and the right compartment contains 1.33 M Mn²+. Calculate the cell potential for this reaction at 298 K. V In this manganese concentration cell, the reaction would proceed spontaneously to transfer Mn²+ Use standard reduction potentials to calculate the equilibrium constant for the reaction: Cd²+ (aq) + Pb(s) → Cd(s) + Pb²+ (aq) From the table of standard reduction potentials: E²+ = -0.403 V, +/Cd Epb²+ = -0.126 V 'Pb²+/Pb Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.
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