Over the years, the mean customer satisfaction rating at a local restaurant has been 75. The restaurant was recently remodeled, and now the managementclaims the mean customer rating, u, is not equal to 75. In a sample of 37 customers chosen at random, the mean customer rating is 80.5. Assume that thepopulation standard deviation of customer ratings is 15.6.Is there enough evidence to support the claim that the mean customer rating is different from 75? Perform a hypothesis test, using the 0.10 level ofsignificance.(a) State the null hypothesis H, and the alternative hypothesis H,.Ho:O0(b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other information to help you with your test.Znns is the value that cuts off an area of 0.05 in the right tail.Z0.05 (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management.O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidenceto support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not enoughevidence to support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enoughevidence to support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is notenough evidence to support the claim that the mean customer rating is not equal 75.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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It is commonly believed that the mean body temperature of a healthy adult is 98.6° F. You are not entirely convinced. You believe that it is not 98.6° F. You collected data using 53 healthy people and found that they had a mean body temperature of 98.33° F with a standard deviation of 0.93 ° F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6° F. a) Identify the null and alternative hypotheses? Họ: ? H1: ? b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed two-tailed c) Identify the appropriate significance level. d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places. e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.
You want to test the speed of your internet connection. You will test the claim that your average speed is greater than 4.3 Mb/s. You collect data 39 different times, and among that sample, the average speed is 4.9 Mb/s. Assume internet speeds are normally distributed with a standard deviation of 1.1 Mb/s.a. State the null and alternative hypothesis for the claim that your average speed is greater than 4.3 Mb/s. Ho: ? ___4.3 Ha: ? ___ 4.3 Please explain to me how you determine the sign that goes into the blank space. b. The (null or alternative) hypothesis is the claim c. The goal of the test is to (support or reject) the claim.
Q2: Serum amylase determinations were made on a sample of 15 apparently healthy subjects in the Electricity Power Plant of Nasriya January 2010. The sample yielded a mean of 96 and a standard deviation of 35 units/100ml. Estimate the true mean of serum amylase in the healthy population of Nasriya.
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Currently patrons at the library speak at an average of 69 decibels. Will this average decline after the installation of a new computer plug in station? After the plug in station was built, the librarian randomly recorded 41 people speaking at the library. Their average decibel level was 67 and their standard deviation was 5. What can be concluded at the the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v| Select an answer v H1: ? v Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean has significantly decreased from 69 at a = 0.01, so there is statistically significant evidence to conclude that the population mean decibel…
An exam score has a mean of 78 and a standard deviation of 9. What is the z-score for an exam score of 64.5? What is the z-score for an exam score of 82.5? Which exam score is more unsual, 64.5 or 82.5? O An exam score of 64.5 is more unsual because its corresponding z-score is further from 0. O An exam score of 82.5 is more unusual because its corresponding z-score is further from 0.
Diabetes Plasma-glucose levels are used to determine the pres- ence of diabetes. Suppose the mean In (plasma-glucose) concentration (mg/dL) in 35- to 44-year-olds is 4.86 with standard deviation = 0.54. A study of 100 sedentary people in this age group is planned to test whether they have a higher or lower level of plasma glucose than the general population. 7.7 If the expected difference is 0.10 In units, then what is the power of such a study if a two-sided test is to be used with a = .05? 7.8 Answer Problem 7.7 if the expected difference is 0.20 In units. 7.9 How many people would need to be studied to have 80% power under the assumptions in Problem 7.7?
On average, Americans have lived in 2 places by the time they are 18 years old. Is this average more for college students? The 66 randomly selected college students who answered the survey question had lived in an average of 2.08 places by the time they were 18 years old. The standard deviation for the survey group was 0.5. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? v Select an answer v H1: ? v| Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) %3D e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... The data suggest that the populaton mean is significantly more than 2 at a = 0.10, so there is statistically significant evidence to conclude that the population mean number of…
Currently patrons at the library speak at an average of 66 decibels. Will this average decline after the installation of a new computer plug in station? After the plug in station was built, the librarian randomly recorded 66 people speaking at the library. Their average decibel level was 63.2 and their standard deviation was 18. What can be concluded at the the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answer v Hị: Select an answer c. The test statistic ? v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... | the null hypothesis. OThe data suggest that the population mean decibal level has not significantly decreased from 66 at a = 0.10, so there is statistically insignificant evidence to conclude that the…
Although, it is commonly believed that the mean for the human body temperature is 98.6 F, others doubt it. A random sample of 100 persons showed the mean body temperature to be 98.4 F with standard deviation of .76 F. At a .05 level of significance, find if the data indicates that the mean for the human body temperature is not equal to 98.6. Find tcritical or tcr
The average American consumes 97 liters of alcohol per year. Does the average college student consume a different amount of alcohol per year? A researcher surveyed 12 randomly selected college students and found that they averaged 79.1 liters of alcohol consumed per year with a standard deviation of 19 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H₁: ? Select an answer ✓ c. The test statistic ? v = (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) d. The p-value =
The annual per capita consumption of fresh bananas (in pounds) can be approximated by a normaldistribution, with a mean of 10.4 pounds and a standard deviation of 3 pounds.a. What is the smallest annual per capita consumption of bananas that can be in the top 10%consumptions?b. What is the largest annual per capita consumption of bananas that can be in the bottom 5% ofconsumptions?

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