Over the years, the mean customer satisfaction rating at a local restaurant has been 75. The restaurant was recently remodeled, and now the managementclaims the mean customer rating, u, is not equal to 75. In a sample of 37 customers chosen at random, the mean customer rating is 80.5. Assume that thepopulation standard deviation of customer ratings is 15.6.Is there enough evidence to support the claim that the mean customer rating is different from 75? Perform a hypothesis test, using the 0.10 level ofsignificance.(a) State the null hypothesis H, and the alternative hypothesis H,.Ho:O0(b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other information to help you with your test.Znns is the value that cuts off an area of 0.05 in the right tail.Z0.05 (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management.O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidenceto support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not enoughevidence to support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enoughevidence to support the claim that the mean customer rating is not equal 75.O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is notenough evidence to support the claim that the mean customer rating is not equal 75.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean consumption of water per household in a city was 1244 cubic feet per month. Due to a water shortage because of a drought, the city council campaigned for water use conservation by households. A few months after the campaign was started, the mean consumption of water for a sample of 96 households was found to be 1164 cubic feet per month. The population standard deviation is given to be 257 cubic feet. a. Find the p-value for the hypothesis test that the mean consumption of water per household has decreased due to the campaign by the city council. Would you reject the null hypothesis at a = 0.025? Round your answer to four decimal places. p-value = We i b. Make the test of part a using the critical-value approach and a = 0.025. Zobserved Round your answer for z to two decimal places. We Ho. i Ho. We conclude that the mean consumption of water per household has due to the campaign by the city council.
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