s. Use the pooled t-test to conduct a left-tailed hypothesis test using a significance level of a= 0.05.
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- In the test of a certain hypothesis the p-valuecorresponding to the test statistics is 0.0316. Can the null hypothesis be rejected at the; i. 0.01 level of significance? ii. 0.05 level of significance? iii. 0.10 level of significancThe display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. LOADING... Click the icon to view the display from technology. Question content area bottom Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=4.00 Mbps H1: μ>4.00 Mbps B. H0: μ<4.00 Mbps H1: μ=4.00 Mbps C. H0: μ=4.00 Mbps H1: μ≠4.00 Mbps T-Test μ<4.00 t=−2.869485 p=0.003303 x=3.43 Sx=1.256322 n=40 Identify the test statistic.Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 350 of the 519 randomly selected wildfires looked at in the south were caused by humans while 383 of the 500 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? Rectangular Snip a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer | (please enter a decimal) Select an answer v Select an answer H1: Select an answer v Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.)
- B. Identify the test statistic. ______ C. Identify the P-value. ____ D. What is the conclusion for this test? The P-value is (greater than/less than) the significance level α, so (reject/ fail to reject) the null hypothesis. There is (sufficient/ insufficient) evidence to support the claim that vinyl gloves have a greater virus leak rate than latex gloves.Test the claim that the proportion of men who own cats is larger than 24% at the .025 significance level. The null and alternative hypothesis would be: Ho:p = 0.24 Ho: = 0.24 Ho: u = 0.24 Ho:p = 0.24 Ho:u = 0.24 Ho:p 0.24 H1:p 0.24 H1:µ > 0.24 H1:µ # 0.24 H:p 0.24 The test is: right-tailed two-tailed left-tailed ㅇ Based on a sample of 60 people, 16 2/3% owned cats The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Submit Question • Previous DEC 11 étvProf. Johnson conducts a hypothesis test on whether the proportion of all UBC students who bike to school (denoted as p) equals 30%. Specifically, Prof.Johnson has H0:p=0.3 versus HA:p≠0.3. He obtains a P-value of 0.01. On the other hand, Prof. Smith would like to test if there is sufficient evidence to support that p is greater than 0.3 at the 10% significance level. Based on Prof. Johnson's result, will the null hypothesis of Prof. Smith's test be rejected? A. There is insufficient information to tell.B. Yes.C. No.
- Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The null and alternative hypothesis would be: Ho: p= 0.8 Ho: ≤ 0.8 Hop: 0.8 Ho:p> 0.8 Ho: 0.8 Ho:p 0.8 H₁:µ 0.8 H₁:p 0.8 The test is: right-tailed two-tailed left-tailed = Based on a sample of 300 people, 82% owned cats The p-value is: (to 2 decimals)A Two tailed test, where the null hypothesis is H0: p = 0.95 and the significance level is 10%. When the edge of the rejection region for the lower tail is 0.9399 then what is the value of "?" in P(P-hat > ? | p = 0.95) = 0.05?Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=0.8H0:μ=0.8H1:μ<0.8H1:μ<0.8 H0:μ=0.8H0:μ=0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 100 people, 87% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
- Test the claim that the mean GPA of night students is significantly different than 3.5 at the 0.05 significance level. The null and alternative hypothesis would be: Ho :p > 0.875 На:р 0.875 O Ho : µ 3.5 Ho :p = 0.875 Ha:p + 0.875 O Ho : µ > 3.5 На: д < 3.5 The test is: O right-tailed left-tailed O two-tailedA personnel director in a particular state claims that the mean annual income is greater in one of the state's counties (county A) than it is in another county (county B). In County A, a random sample of 6 residents has a mean annual income of $41,400 and a standard deviation of $8400. In County B, a random sample of 8 residents has a mean annual income of $39,800 and a standard deviation of $5200. At a = 0.10, answer parts (a) through (e). Assume the population variances are not equal. If convenient, use technology to solve the problem. (a) Identify the claim and state Ho and Ha. Which is the correct claim below? A. "The mean annual income in county A is less than in county B." B. "The mean annual incomes in counties A and B are not equal." C. "The mean annual incomes in counties A and B are equal." D. "The mean annual income in county A is greater than in county B." What are H, and Ha? The null hypothesis, Ho, is The alternative hypothesis, Ha, is Which hypothesis is the claim? The…The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b), determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a right-tailed test is z=2.00. The P-value is . (Round to three decimal places as needed.)