S²- Previous-8. What is the major preferred ion of S? Previous-9. Please give the electron configuration of that S ion. 1s² 2s² 2p 3s² 3p 1. Is the ionic radius of that ion larger or smaller than the atomic radius of S? 2. What are 2 other reasonable options for ions S can form? S2+ and Larger 3. Why? Demonstrate them: (Hint-hint: Show before and after Orbital Diagrams!)
Electronic Transitions and Spectroscopy
The term “electronic” connotes electron, and the term “transition” implies transformation. In a molecule, the electrons move from a lower to a higher energy state due to excitation. The two energy states, the ground state and the excited state are the lowest and the highest energy states, respectively. An energy change is observed with this transition, which depicts the various data related to the molecule.
Photoelectron Spectroscopy
Photoelectron spectroscopy (PES) is a part of experimental chemistry. It is a technique used in laboratories that involves projecting intense beams of radiation on a sample element. In response, the element ejects electrons for which the relative energies are measured.
Neutral atoms show a tendency to donate or accept electrons to attain the octet configuration and thereby attain stability.
An octet configuration represents a state in which there are 8 electrons in the valence shell of the atom. Some elements gain electrons to form negatively charged ions known as anions while others lose electrons to form positively charged ions called cations.
Cations are smaller than the neutral atom due to the excess positive charge generated in the nucleus due to the loss of negatively charged electrons. On the other hand, the anions are larger than the neutral atoms. This is because the attraction between the nucleus and valence electrons decreases due to the increase in the number of electrons.
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