Take your time answer the questions, this is all one question, please answer correctly, thank you very much, will write an wonderful review when solutions are done. 5. Two-tailed hypothesis testing - Step by stepS-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms.Suppose that a researcher is interested in testing SAM-e on patients who are struggling with cancer. She obtains a sample of n = 30 patientsand asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the BeckDepression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression.The scores from the sample produced a mean of M = 26.2 with a standard deviation of s = 2.97. In the general population of cancer patients, thestandardized test is known to have a population mean of μ = 28.1. Because there are no previous studies using SAM-e with this population, theresearcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis.From the following, select the correct null and alternative hypotheses for this study:Ho: USAM-e * 28.1; H₁: USAM-e = 28.1O Ho: USAM-e ≤28.1; H₁: USAM-e > 28.1Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees offreedom. There are degrees of freedom.Ho: USAM-e = 28.1; H₁: USAM-e * 28.1Use the t distribution table to find the critical region for a = 0.05.Ho: USAM-e 2 28.1; H₁: USAM-e < 28.1The t Distribution:4Proportion in One Tail0.10 0.05 0.025 0.01 0.005Proportion in Two Tails Combineddf0.500.20 0.10 0.05 0.020.0163.6571 1.000 3.078 6.314 12.706 31.82120.816 1.8866.965 9.92532.920 4.3030.765 1.638 2.353 3.182 4.5410.741 1.533 2.132 2.776 3.7475.8414.6040.727 1.476 2.015 2.571 3.365 4.0320.718 1.440 1.9432.4473.143 3.70773.4990.711 1.415 1.895 2.3658 0.706 1.397 1.8602.9982.896 3.3559 0.703 1.383 1.83310 0.700 1.372 1.81211 0.697 1.363 1.796 2.201 2.718 3.1062.3062.262 2.821 3.2502.228 2.764 3.169560.25 12 0.695 1.356 1.782 2.1792.6813.05513 0.694 1.3501.7712.160 2.6503.012140.692 1.3451.761 2.145 2.6242.977150.691 1.341 1.7532.1312.6022.947160.690 1.337 1.7462.1202.5832.921170.6891.333 1.740 2.110 2.5672.898180.688 1.330 1.734 2.1012.5522.878190.688 1.328 1.7292.0932.539 2.861200.6871.325 1.7252.0862.5282.845210.6861.323 1.7212.0802.5182.831220.6861.3211.7172.0742.5082.819230.6851.319 1.714 2.0692.5002.807240.685 1.318 1.7112.0642.4922.79725 0.684 1.316 1.7082.0602.4852.787261.315 1.7062.0562.4792.7790.6840.684 1.314271.703 2.0522.4732.77128 0.683 1.313 1.7012.048 2.4672.76329 0.683 1.311 1.6992.0452.4622.7562.042 2.4572.7503040 0.681 1.3030.683 1.310 1.6971.6842.0212.4232.7042.000 2.3902.66060 0.679 1.296 1.671120 0.677 1.289 1.6581.9802.358 2.6170.674 1.282 1.645 1.960 2.326 2.576The critical t scores (the values that define the borders of the critical region) areThe estimated standard error isThe t statistic isThe t statisticTherefore, the researcherin the critical region. Therefore, the null hypothesisrejected.conclude that SAM-e has a significant effect on the moods of cancer patients.

Given Data, Sample size, n = 30 Population mean, μ = 28.1 Sample mean, M = 26.2 Sample standard…

Answered: S-adenosyl methionine (SAM-e) is a…

S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Take your time answer the questions, this is all one question, please answer correctly, thank you very much, will write an wonderful review when solutions are done.

5. Two-tailed hypothesis testing - Step by step
S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms.
Suppose that a researcher is interested in testing SAM-e on patients who are struggling with cancer. She obtains a sample of n = 30 patients
and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck
Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression.
The scores from the sample produced a mean of M = 26.2 with a standard deviation of s = 2.97. In the general population of cancer patients, the
standardized test is known to have a population mean of μ = 28.1. Because there are no previous studies using SAM-e with this population, the
researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis.
From the following, select the correct null and alternative hypotheses for this study:
Ho: USAM-e * 28.1; H₁: USAM-e = 28.1
O Ho: USAM-e ≤28.1; H₁: USAM-e > 28.1
Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of
freedom. There are degrees of freedom.
Ho: USAM-e = 28.1; H₁: USAM-e * 28.1
Use the t distribution table to find the critical region for a = 0.05.
Ho: USAM-e 2 28.1; H₁: USAM-e < 28.1
The t Distribution:
4
Proportion in One Tail
0.10 0.05 0.025 0.01 0.005
Proportion in Two Tails Combined
df
0.50
0.20 0.10 0.05 0.02
0.01
63.657
1 1.000 3.078 6.314 12.706 31.821
2
0.816 1.886
6.965 9.925
3
2.920 4.303
0.765 1.638 2.353 3.182 4.541
0.741 1.533 2.132 2.776 3.747
5.841
4.604
0.727 1.476 2.015 2.571 3.365 4.032
0.718 1.440 1.943
2.447
3.143 3.707
7
3.499
0.711 1.415 1.895 2.365
8 0.706 1.397 1.860
2.998
2.896 3.355
9 0.703 1.383 1.833
10 0.700 1.372 1.812
11 0.697 1.363 1.796 2.201 2.718 3.106
2.306
2.262 2.821 3.250
2.228 2.764 3.169
5
6
0.25

12 0.695 1.356 1.782 2.179
2.681
3.055
13 0.694 1.350
1.771
2.160 2.650
3.012
14
0.692 1.345
1.761 2.145 2.624
2.977
15
0.691 1.341 1.753
2.131
2.602
2.947
16
0.690 1.337 1.746
2.120
2.583
2.921
17
0.689
1.333 1.740 2.110 2.567
2.898
18
0.688 1.330 1.734 2.101
2.552
2.878
19
0.688 1.328 1.729
2.093
2.539 2.861
20
0.687
1.325 1.725
2.086
2.528
2.845
21
0.686
1.323 1.721
2.080
2.518
2.831
22
0.686
1.321
1.717
2.074
2.508
2.819
23
0.685
1.319 1.714 2.069
2.500
2.807
24
0.685 1.318 1.711
2.064
2.492
2.797
25 0.684 1.316 1.708
2.060
2.485
2.787
26
1.315 1.706
2.056
2.479
2.779
0.684
0.684 1.314
27
1.703 2.052
2.473
2.771
28 0.683 1.313 1.701
2.048 2.467
2.763
29 0.683 1.311 1.699
2.045
2.462
2.756
2.042 2.457
2.750
30
40 0.681 1.303
0.683 1.310 1.697
1.684
2.021
2.423
2.704
2.000 2.390
2.660
60 0.679 1.296 1.671
120 0.677 1.289 1.658
1.980
2.358 2.617
0.674 1.282 1.645 1.960 2.326 2.576
The critical t scores (the values that define the borders of the critical region) are
The estimated standard error is
The t statistic is
The t statistic
Therefore, the researcher
in the critical region. Therefore, the null hypothesis
rejected.
conclude that SAM-e has a significant effect on the moods of cancer patients.

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