rove the following statement using mathematical induction. Do not derive it from Theorem 5.2.1 or Theorem 5.2.2. n(5n - 3) For every integer n2 1, 1 + 6 + 11 + 16 +... + (5n - 4) = 2
rove the following statement using mathematical induction. Do not derive it from Theorem 5.2.1 or Theorem 5.2.2. n(5n - 3) For every integer n2 1, 1 + 6 + 11 + 16 +... + (5n - 4) = 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Prove the following statement using mathematical induction. Do not derive it from Theorem 5.2.1 or Theorem 5.2.2.
For every integer \( n \geq 1, 1 + 6 + 11 + 16 + \ldots + (5n - 4) = \frac{n(5n - 3)}{2} \).
**Proof (by mathematical induction):** Let \( P(n) \) be the equation
\[ 1 + 6 + 11 + 16 + \ldots + (5n - 4) = \frac{n(5n - 3)}{2} \]
We will show that \( P(n) \) is true for every integer \( n \geq 1 \).
**Show that \( P(1) \) is true:** Select \( P(1) \) from the choices below.
- \( P(1) = 5 \cdot 1 - 4 \)
- \( 1 = \frac{1 \cdot (5 \cdot 1 - 3)}{2} \)
- \( 1 + (5 \cdot 1 - 4) = 1 \cdot (5 \cdot 1 - 3) \)
- \( P(1) = 1 \cdot \frac{(5 \cdot 1 - 3)}{2} \)
The selected statement is true because both sides of the equation equal \_\_\_\_\_\_\_\_\_\_.
**Show that for each integer \( k \geq 1 \), if \( P(k) \) is true, then \( P(k + 1) \) is true:**
Let \( k \) be any integer with \( k \geq 1 \), and suppose that \( P(k) \) is true. The left-hand side of \( P(k) \) is \_\_\_\_\_\_\_\_\_\_, and the right-hand side of \( P(k) \) is \_\_\_\_\_\_\_\_\_\_.
*[The inductive hypothesis states that the two sides of \( P(k) \) are equal.]*
We must show that \( P(k + 1) \) is true. \( P(k + 1) \) is the equation \( 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc357075-d330-4116-93bc-b2819b26405c%2Fa308a57b-4811-47ec-ad54-5d5559f61481%2Fpl9l63_processed.png&w=3840&q=75)
Transcribed Image Text:Prove the following statement using mathematical induction. Do not derive it from Theorem 5.2.1 or Theorem 5.2.2.
For every integer \( n \geq 1, 1 + 6 + 11 + 16 + \ldots + (5n - 4) = \frac{n(5n - 3)}{2} \).
**Proof (by mathematical induction):** Let \( P(n) \) be the equation
\[ 1 + 6 + 11 + 16 + \ldots + (5n - 4) = \frac{n(5n - 3)}{2} \]
We will show that \( P(n) \) is true for every integer \( n \geq 1 \).
**Show that \( P(1) \) is true:** Select \( P(1) \) from the choices below.
- \( P(1) = 5 \cdot 1 - 4 \)
- \( 1 = \frac{1 \cdot (5 \cdot 1 - 3)}{2} \)
- \( 1 + (5 \cdot 1 - 4) = 1 \cdot (5 \cdot 1 - 3) \)
- \( P(1) = 1 \cdot \frac{(5 \cdot 1 - 3)}{2} \)
The selected statement is true because both sides of the equation equal \_\_\_\_\_\_\_\_\_\_.
**Show that for each integer \( k \geq 1 \), if \( P(k) \) is true, then \( P(k + 1) \) is true:**
Let \( k \) be any integer with \( k \geq 1 \), and suppose that \( P(k) \) is true. The left-hand side of \( P(k) \) is \_\_\_\_\_\_\_\_\_\_, and the right-hand side of \( P(k) \) is \_\_\_\_\_\_\_\_\_\_.
*[The inductive hypothesis states that the two sides of \( P(k) \) are equal.]*
We must show that \( P(k + 1) \) is true. \( P(k + 1) \) is the equation \( 1
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