Provide a combinatorial proof (argue that both sides count the same thing) for the following: 1+2+...+x = ((x+1) choose 2) Note: This is usually proven by induction but please refrain from using any induction in this proof. Hint: The above equation is also written as 1+2+...+x = (x(x+1))/2

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A: Assume the result is true then obtain a contradiction.

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