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(Round to three decimal places as needed.) (c) Construct and interpret a 95 % confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without Select the correct choice below and fill in any answer boxes within your choice (Type integers or decimals rounded to three decimal places as needed Use ascending order) OA. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between and OB. We are confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and

(Round to three decimal places as needed.) (c) Construct and interpret a 95 % confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without Select the correct choice below and fill in any answer boxes within your choice (Type integers or decimals rounded to three decimal places as needed Use ascending order) OA. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between and OB. We are confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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C)

A random sample of 1008 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1008 adults surveyed, 519 indicated that televisions are a luxury they could do without. Complete parts (a) through (e) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). EC (a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions are a luxury they could do without. p = 515 (Round to three decimal places as needed.) (b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample is stated to be a simple random sample, the value of np (1-p) is 251.773, which is greater than or equal to 10, and the (Round to three decimal places as needed.) (c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order) OA. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between OB. We are % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and and sample size can be assumed to be less than or equal to 5% of the population size.
Transcribed Image Text:A random sample of 1008 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1008 adults surveyed, 519 indicated that televisions are a luxury they could do without. Complete parts (a) through (e) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). EC (a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions are a luxury they could do without. p = 515 (Round to three decimal places as needed.) (b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample is stated to be a simple random sample, the value of np (1-p) is 251.773, which is greater than or equal to 10, and the (Round to three decimal places as needed.) (c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order) OA. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between OB. We are % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and and sample size can be assumed to be less than or equal to 5% of the population size.
Standard Normal Distribution Table (page 1) Area Z -3.4 -3.2 -29 -2.8 -2.7 -2.6 -2.5 -2.4 -2.2 -1.9 -1.8 0.00 0:0003 0.0005 0.0007 0.0010 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107 0.01.39 0.0179 0.0228 0.0287 0.0359 0.01 0.0003 0.0005 0.0007 0.0009 0.0013 0.0018 0.0025 0.0034 0.0045 0.0060 0.0080 0.0104 0.0136 0.0174 0.0222 0.0281 0.0351 0.02 0.0003 0.0005 0.0006 0.0009 0.0013 0.0018 0.0024 0.0033 0.0044 0.0059 0.0078 0.0102 0.0132 0.0170 0.0217 0.0274 0.0344 Standard Normal Distribution 0.03 0.04 0.05 0.0003 0.0004 0.0006 0.0009 0.0012 0.00 17 0.0023 0.0032 0.0043 0.0057 0.0075 0.0099 0.0129 0.0166 0.0212 0.0268 0.0336 Print 0.0003 0.0004 0.0006 0.0008 0.0012 0.0016 0.0023 0.0031 0.0041 0.0055 0.0073 0.0096 0.0125 0.0162 0.0207 0.0262 0.0329 0.0003 0.0004 0.0006 0.0008 0.0011 0.0016 0.0022 0.0030 0.0040 0.0054 0.0071 0.0004 0.0122 0.0158 0.0202 0.0256 0.0322 Done 0.00 0.0003 0.0004 0.0006 0.0008 0.0011 0.0015 0.0021 0.0029 0.0039 0.0052 0.0069 0.0091 0.0119 0.0154 0.0197 0.0250 0.0314 0.07 0.0003 0.0004 0.0005 0.0008 0.0011 0.0015 0.0021 0.0028 0.0038 0.0051 0.0068 0.0089 0.0116 0.0150 0.0192 0.0244 0.0307 0.08 0.0003 0.0004 0.0005 0.0007 0.0010 0.0014 0.0020 0.0027 0.0037 0.0049 0.0066 0.0087 0.0113 0.0146 0.0188 0.0239 0.0301 0.09 0.0002 0.0003 0.0005 0.0007 0.0010 0.0014 0,0019 0.0026 0.0036 0.0048 0.0064 0.0084 0.0110 0.0143 0.0183 0.0233 0.0294
Transcribed Image Text:Standard Normal Distribution Table (page 1) Area Z -3.4 -3.2 -29 -2.8 -2.7 -2.6 -2.5 -2.4 -2.2 -1.9 -1.8 0.00 0:0003 0.0005 0.0007 0.0010 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107 0.01.39 0.0179 0.0228 0.0287 0.0359 0.01 0.0003 0.0005 0.0007 0.0009 0.0013 0.0018 0.0025 0.0034 0.0045 0.0060 0.0080 0.0104 0.0136 0.0174 0.0222 0.0281 0.0351 0.02 0.0003 0.0005 0.0006 0.0009 0.0013 0.0018 0.0024 0.0033 0.0044 0.0059 0.0078 0.0102 0.0132 0.0170 0.0217 0.0274 0.0344 Standard Normal Distribution 0.03 0.04 0.05 0.0003 0.0004 0.0006 0.0009 0.0012 0.00 17 0.0023 0.0032 0.0043 0.0057 0.0075 0.0099 0.0129 0.0166 0.0212 0.0268 0.0336 Print 0.0003 0.0004 0.0006 0.0008 0.0012 0.0016 0.0023 0.0031 0.0041 0.0055 0.0073 0.0096 0.0125 0.0162 0.0207 0.0262 0.0329 0.0003 0.0004 0.0006 0.0008 0.0011 0.0016 0.0022 0.0030 0.0040 0.0054 0.0071 0.0004 0.0122 0.0158 0.0202 0.0256 0.0322 Done 0.00 0.0003 0.0004 0.0006 0.0008 0.0011 0.0015 0.0021 0.0029 0.0039 0.0052 0.0069 0.0091 0.0119 0.0154 0.0197 0.0250 0.0314 0.07 0.0003 0.0004 0.0005 0.0008 0.0011 0.0015 0.0021 0.0028 0.0038 0.0051 0.0068 0.0089 0.0116 0.0150 0.0192 0.0244 0.0307 0.08 0.0003 0.0004 0.0005 0.0007 0.0010 0.0014 0.0020 0.0027 0.0037 0.0049 0.0066 0.0087 0.0113 0.0146 0.0188 0.0239 0.0301 0.09 0.0002 0.0003 0.0005 0.0007 0.0010 0.0014 0,0019 0.0026 0.0036 0.0048 0.0064 0.0084 0.0110 0.0143 0.0183 0.0233 0.0294
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