Round the answers in the table to four decimal places. Source of Degrees of Freedom Sum of Squares Mean Square Value of the Test Statistic Variation Between 2 17.3582 Within 83.5663 Total 11 (b) Using a = 0.01, what is your conclusion for the test with the null hypothesis that the means of the three populations are equal against the alternate hypothesis that the means of the three populations are not equal? We will the null hypothesis that the means of the three populations are equal.
Round the answers in the table to four decimal places. Source of Degrees of Freedom Sum of Squares Mean Square Value of the Test Statistic Variation Between 2 17.3582 Within 83.5663 Total 11 (b) Using a = 0.01, what is your conclusion for the test with the null hypothesis that the means of the three populations are equal against the alternate hypothesis that the means of the three populations are not equal? We will the null hypothesis that the means of the three populations are equal.
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Transcribed Image Text:The following ANOVA table, based on information obtained for three samples selected from three independent populations that are
normally distributed with equal variances, has a few values missing.
Note: Use Table VII in Appendix C to find critical Fvalues for given df.
(a) Find the missing values and complete the ANOVA table.
Round the answers in the table to four decimal places.
Source of
Degrees of Freedom
Sum of Squares
Mean Square
Value of the Test Statistic
Variation
Between
2
17.3582
Within
83.5663
Total
11
(b) Using a = 0.01, what is your conclusion for the test with the null hypothesis that the means of the three populations are equal
against the alternate hypothesis that the means of the three populations are not equal?
the null hypothesis that the means of the three populations are equal.
We will
e Тext
fail to reject
reject
Expert Solution

Step 1
let us first understand the generalized ANOVA table.
source of variation | degrees of freedom | sum of squares | mean square | F |
between | k-1 | SSB | SSB/K-1 | MSSB/MSSW |
within | n-k | SSW | SSW/N-K | |
total | n-1 | SST |
where n is total sample size ,k is number of treatment .
hence for the above table
degrees of freedom for error (within )=total degrees of freedom- treatment (between)degrees of freedom
SSB=degrees of freedom (between)* mean SSB
total SS=SSB + SSW
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