rom the following heats of combustion,   CH3OH(l) + 3/2O2(g) →CO2(g) + 2H2O(l)    ΔHrxn = −726.4 kJ/mol   C(graphite) + O2(g) →CO2(g)    ΔHrxn = −393.5 kJ/mol   H2(g) + 1/2O2(g) → H2O(l)    ΔH rxn = −285.8 kJ/mol   Calculate the enthalpy of formation of methanol (CH3OH) from its elements:   C(graphite) + 2H2(g) + 1/2O2(g) →CH3OH(l)

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.21QE
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rom the following heats of combustion,
 

CH3OH(l) + 3/2O2(g) →CO2(g) + 2H2O(l)
 
 ΔHrxn = −726.4 kJ/mol
 
C(graphite) + O2(g) →CO2(g)
 
 ΔHrxn = −393.5 kJ/mol
 
H2(g) + 1/2O2(g) → H2O(l)
 
 ΔH rxn = −285.8 kJ/mol

 
Calculate the enthalpy of formation of methanol (CH3OH) from its elements:
 
C(graphite) + 2H2(g) + 1/2O2(gCH3OH(l)

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