rod of length L and mass ʼm' about an axis Q. 47 : The moment of inertia of a thin uniform a point at distance of 3 (b) through , from its one SEI
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A: Solution:-Step 1: Step 2: Step 3:
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A: By parallel axis theorem, the moment of inertia at 2R is I = (2MR2/5) + M(2R)2 I = 22MR2/5
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A: The figure shows the moment of inertia of the rod,
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A: Given:α = 31 rad/s2I =0.64 kg m2r =2.25 cm = 2.25×10-2 m
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A: Givenr = 8.5 mω0= 0α = 0.025 rad/s2I = 7.8 ×105 kg m2t = 30 sec
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A: GivenIntial speed, u=1.8 m/sMass of each skaters, m=70 kgcenter of mass are at distance, r=0.89 m
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Q: Q) A non-uniform thin rod of length L and mass m ,is located along the x axis as shown in fig. If…
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