RLC circuit: d²q L +R- dq 1 + dt² dt9 = Vocos (wt) a) Find a particular solution for this differential equation. b) Use the given differential equation to derive a differential equation for the current. (hint: i(t) = d) c) Given two constants A and B, find D and ☀ such that Acos(wt) + Bsin(wt) Dcos(wt – 6) is satisfied for any wt. (hint: use appropriate trigonometric identities) d) Use part C to show that the particular solution of part a can be written as: =
RLC circuit: d²q L +R- dq 1 + dt² dt9 = Vocos (wt) a) Find a particular solution for this differential equation. b) Use the given differential equation to derive a differential equation for the current. (hint: i(t) = d) c) Given two constants A and B, find D and ☀ such that Acos(wt) + Bsin(wt) Dcos(wt – 6) is satisfied for any wt. (hint: use appropriate trigonometric identities) d) Use part C to show that the particular solution of part a can be written as: =
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![RLC circuit:
d²q dq 1
+ R
+
dt²
L
dt = Vocos (wt)
a) Find a particular solution for this differential equation.
b) Use the given differential equation to derive a differential equation for the current.
(hint: i(t) = d)
c) Given two constants A and B, find D and o such that Acos(wt) + Bsin(wt)
Dcos(wt - ) is satisfied for any wt. (hint: use appropriate trigonometric identities)
d) Use part C to show that the particular solution of part a can be written as:
Vo
√(C−¹ − Lw²)² + R²w²
= cos(wt - p)
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8a9969b-d178-4c75-a7d3-b4b92541fde7%2F0ac5a9c5-5dba-477b-8280-3bf910c7b2db%2Fn9ubplw_processed.png&w=3840&q=75)
Transcribed Image Text:RLC circuit:
d²q dq 1
+ R
+
dt²
L
dt = Vocos (wt)
a) Find a particular solution for this differential equation.
b) Use the given differential equation to derive a differential equation for the current.
(hint: i(t) = d)
c) Given two constants A and B, find D and o such that Acos(wt) + Bsin(wt)
Dcos(wt - ) is satisfied for any wt. (hint: use appropriate trigonometric identities)
d) Use part C to show that the particular solution of part a can be written as:
Vo
√(C−¹ − Lw²)² + R²w²
= cos(wt - p)
=
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