QuestionsRing charge This was left as an exercise. Consider the following ring of charge with radius R andtotal charge Q. Show that the expression (or the integral) for the electric field at pointP is given byEz=RkQz(2²+R²)³/2rE.Disc charge Now let's see how we can use the above result to find the electric field due to a chargeddisc. Typically for a disc you would need to evaluate a 2D integral, but if you imagethe disc as an accumulation of ring charges, the integral is effectively 1D¹.EpPRZO = area chargedensityRdR'¹Hint: Think about how you would express dQ = odA can be expressed in terms of dR, i.e. how wouldA and R relate (hence dA with dR).

Answered: Ring charge This was left as an…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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$\begin{array}{l} G i v e n : \\ r i n g h a s r a d i u s, R \\ p o i n t P i s r f r o m t h e r i n g a n d z f r o m c e n t e r o f t h e r i n g \\ t o t a l c h a r g e o n t h e r i n g, Q \\ A s k e d : \\ T o s h o w t h a t e l e c t r i c f i e l d (E F) a t P i s \\ E_{z} = \frac{k Q z}{{(z^{2} + R^{2})}^{3 / 2}} \\ u s e t h i s t o d e r i v e E F a t P d u e t o a d i s c . \end{array}$

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