Richard and Jessica are lab partners. They pour 40.0 mL of a 0.200 M HC2H3O2 solution into a 250 mL flask. They then set up a burette and add 0.250 M NaOH solution to the burette. They are asked to fill in the table below. The first box asks for the pH of the acetic acid without any NaOH added. The second through tenth boxes show the pH after the indicated amounts of NaOH are added to the acetic acid solution. Please show your work for the first, sixth and tenth boxes. The initial reaction is: H₂O (L) + HC2H3O2 (aq) = H₂O* (aq) + C₂H₂O₂ with Ka = 1.8 x 105 and the reaction involving NaOH is: NaOH (aq) + HC₂H₂O₂ (aq) = H₂O (L) + C₂H₂O₂ (aq). mL of NaOH added pH Box 1 work 0.00 2.72 4.00 8.00 3.46 3.99 12.00 16.00 4.37 H3O+ HCz HyOz | Hz H3 C2H3O2 20.00 24.00 28.00 32.00 36.00 Initial .200 0 PH= 2.72 change -X X X Equilibrium 200-x 1.8×10-5 = x² X X = 3.6 × 10-6 = √x²= √3.6×10-6 1 .200 Box 6 work Box 10 work [H 301 = 0.00189 pH = 100 [H3O+] =
Richard and Jessica are lab partners. They pour 40.0 mL of a 0.200 M HC2H3O2 solution into a 250 mL flask. They then set up a burette and add 0.250 M NaOH solution to the burette. They are asked to fill in the table below. The first box asks for the pH of the acetic acid without any NaOH added. The second through tenth boxes show the pH after the indicated amounts of NaOH are added to the acetic acid solution. Please show your work for the first, sixth and tenth boxes. The initial reaction is: H₂O (L) + HC2H3O2 (aq) = H₂O* (aq) + C₂H₂O₂ with Ka = 1.8 x 105 and the reaction involving NaOH is: NaOH (aq) + HC₂H₂O₂ (aq) = H₂O (L) + C₂H₂O₂ (aq). mL of NaOH added pH Box 1 work 0.00 2.72 4.00 8.00 3.46 3.99 12.00 16.00 4.37 H3O+ HCz HyOz | Hz H3 C2H3O2 20.00 24.00 28.00 32.00 36.00 Initial .200 0 PH= 2.72 change -X X X Equilibrium 200-x 1.8×10-5 = x² X X = 3.6 × 10-6 = √x²= √3.6×10-6 1 .200 Box 6 work Box 10 work [H 301 = 0.00189 pH = 100 [H3O+] =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Richard and Jessica are lab partners. They pour 40.0 mL of a 0.200 M HC2H3O2 solution into a 250 mL flask. They then set
up a burette and add 0.250 M NaOH solution to the burette. They are asked to fill in the table below. The first box asks
for the pH of the acetic acid without any NaOH added. The second through tenth boxes show the pH after the indicated
amounts of NaOH are added to the acetic acid solution. Please show your work for the first, sixth and tenth boxes. The
initial reaction is: H₂O (L) + HC2H3O2 (aq) = H₂O* (aq) + C₂H₂O₂ with Ka = 1.8 x 105 and the reaction
involving NaOH is: NaOH (aq) + HC₂H₂O₂ (aq) = H₂O (L) + C₂H₂O₂ (aq).
mL of NaOH added
pH
Box 1 work
0.00
2.72
4.00
8.00
3.46 3.99
12.00 16.00
4.37
H3O+
HCz HyOz | Hz
H3
C2H3O2
20.00
24.00 28.00
32.00
36.00
Initial
.200
0
PH= 2.72
change
-X
X
X
Equilibrium 200-x
1.8×10-5 = x²
X
X
=
3.6 × 10-6 = √x²= √3.6×10-6
1
.200
Box 6 work
Box 10 work
[H 301 = 0.00189 pH = 100 [H3O+] =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5abad2ef-7d64-4544-b6f7-dd3dfbff74f8%2Fbf84e70b-8fb9-4e0f-a024-60ffbc193f0a%2Fkj0xq0f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Richard and Jessica are lab partners. They pour 40.0 mL of a 0.200 M HC2H3O2 solution into a 250 mL flask. They then set
up a burette and add 0.250 M NaOH solution to the burette. They are asked to fill in the table below. The first box asks
for the pH of the acetic acid without any NaOH added. The second through tenth boxes show the pH after the indicated
amounts of NaOH are added to the acetic acid solution. Please show your work for the first, sixth and tenth boxes. The
initial reaction is: H₂O (L) + HC2H3O2 (aq) = H₂O* (aq) + C₂H₂O₂ with Ka = 1.8 x 105 and the reaction
involving NaOH is: NaOH (aq) + HC₂H₂O₂ (aq) = H₂O (L) + C₂H₂O₂ (aq).
mL of NaOH added
pH
Box 1 work
0.00
2.72
4.00
8.00
3.46 3.99
12.00 16.00
4.37
H3O+
HCz HyOz | Hz
H3
C2H3O2
20.00
24.00 28.00
32.00
36.00
Initial
.200
0
PH= 2.72
change
-X
X
X
Equilibrium 200-x
1.8×10-5 = x²
X
X
=
3.6 × 10-6 = √x²= √3.6×10-6
1
.200
Box 6 work
Box 10 work
[H 301 = 0.00189 pH = 100 [H3O+] =
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