Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 69 A's in the 20th position You can use the Distribution Calculators page in SALT to find critical values and/or p-values to answer parts of this question. Please note that the Inferential Statistics page does not use the continuity-corrected version the test statistic. (a) If the probability of an A in the 20th position in ribosomal 5S RNA 0.79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method. (Use a = 0.05.) State the null and alternative hypotheses. (Enter != for as needed.) Ho: H₁: Find the test statistic. (Round your answer to two decimal places.) Find the critical value. (Round your answer to two decimal places.) State your conclusion. O Fail to reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Fail to reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. (b) Use technology to report a p-value corresponding to your results in (a). (Round your answer to four decimal places.) p-value=
Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 69 A's in the 20th position You can use the Distribution Calculators page in SALT to find critical values and/or p-values to answer parts of this question. Please note that the Inferential Statistics page does not use the continuity-corrected version the test statistic. (a) If the probability of an A in the 20th position in ribosomal 5S RNA 0.79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method. (Use a = 0.05.) State the null and alternative hypotheses. (Enter != for as needed.) Ho: H₁: Find the test statistic. (Round your answer to two decimal places.) Find the critical value. (Round your answer to two decimal places.) State your conclusion. O Fail to reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. O Fail to reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA. (b) Use technology to report a p-value corresponding to your results in (a). (Round your answer to four decimal places.) p-value=
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 21PPS
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Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with
different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 69 A's in the 20th position.
You can use the Distribution Calculators page in SALT to find critical values and/or p-values to answer parts of this question. Please note that the Inferential Statistics page does not use the continuity-corrected version of
the test statistic.
(a) If the probability of an A in the 20th position in ribosomal 5S RNA is 0.79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method. (Use α = 0.05.)
State the null and alternative hypotheses. (Enter != for ‡ as needed.)
Ho:
H₁:
Find the test statistic. (Round your answer to two decimal places.)
Find the critical value. (Round your answer to two decimal places.)
State your conclusion.
Fail to reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
Reject Ho. There is sufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
Reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
Fail to reject Ho. There is insufficient evidence to conclude that the new sequence is different from ribosomal 5S RNA.
(b) Use technology to report a p-value corresponding to your results in (a). (Round your answer to four decimal places.)
p-value =
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