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RF ww 12.15 The circuit of Figure P12.15 will remove the DC portion of the input voltage, vi (t), while amplifying the AC portion. Let vi (t) = 10 + 10- sin wt V, Rf = 10 k2, and Vbatt = 20 V. a. Find Rs such that no DC voltage appears at the output. b What is v. (t) using Re from part a? Voat Vour(t) v;(1) Figure P12.15

RF ww 12.15 The circuit of Figure P12.15 will remove the DC portion of the input voltage, vi (t), while amplifying the AC portion. Let vi (t) = 10 + 10- sin wt V, Rf = 10 k2, and Vbatt = 20 V. a. Find Rs such that no DC voltage appears at the output. b What is v. (t) using Re from part a? Voat Vour(t) v;(1) Figure P12.15

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question

For part(a) of the question, how is 10-3sin(wt) got rid in the equation after "no DC in output..."

Also, why is the KCL eqn at the node : Is+Iin = If    instead of Is+If = Iin ? Does it matter whcih direction of current i choose?

RF ww 12.15 The circuit of Figure P12.15 will remove the DC portion of the input voltage, v (t), while amplifying the AC portion. Let vi (t) = 10 + 10-3 sin ot V, Rf = 10 k2, and Voatt = 20 V. a. Find Rs such that no DC voltage appears at the output. b. What is vout (1), using Rs from part a? Rs Voatt Vour(1) vị(1) Figure P12.15 (a:10K, b: 2×10* sinot) swers: (a) Inverting node: (V* - Vbatt)/Rs = (Vout-V)/RF V = (Vout Rs/RF +Vbatt) Rf/(Rs+RF) Non-inverting side: V* = V1 = 10+10³ sinøt Negative feedback V* = V (Vout Rs/RF +Vbatt) Rf/(Rs+Rf) = 10+10³sin@t Vout×Rs/RF = (10+10³ sinot) (Rs+Rf)/RF -Vbatt No DC in output, means: 10 (Rs+Rf)/RF -Vbatt Rs = RF (Vbatt/10 -1) = 10k (20/10-1) = 10K
Transcribed Image Text:RF ww 12.15 The circuit of Figure P12.15 will remove the DC portion of the input voltage, v (t), while amplifying the AC portion. Let vi (t) = 10 + 10-3 sin ot V, Rf = 10 k2, and Voatt = 20 V. a. Find Rs such that no DC voltage appears at the output. b. What is vout (1), using Rs from part a? Rs Voatt Vour(1) vị(1) Figure P12.15 (a:10K, b: 2×10* sinot) swers: (a) Inverting node: (V* - Vbatt)/Rs = (Vout-V)/RF V = (Vout Rs/RF +Vbatt) Rf/(Rs+RF) Non-inverting side: V* = V1 = 10+10³ sinøt Negative feedback V* = V (Vout Rs/RF +Vbatt) Rf/(Rs+Rf) = 10+10³sin@t Vout×Rs/RF = (10+10³ sinot) (Rs+Rf)/RF -Vbatt No DC in output, means: 10 (Rs+Rf)/RF -Vbatt Rs = RF (Vbatt/10 -1) = 10k (20/10-1) = 10K
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