Review Part A - Transmitted power A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D = 2.25 in and the machine operates at w = 120 rpm .If the allowable shear stress in the shaft is 12 ksi , what is the maximum power transmissible to the machine? Express your answer with appropriate units to three significant figures. • View Available Hint(s) HẢ ? P = 38110.711 Нр

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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need help with this review part A

engineering of materials

 

Power Transmission
4 of 10
>
I Review
Part A - Transmitted power
Learning Goal:
To determine the maximum possible power
A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D = 2.25 in and the machine operates at w = 120 rpm
If the allowable shear stress in the shaft is 12 ksi , what is the maximum power transmissible to the machine?
transmission for a circular shaft and the minimum
diameter required to avoid exceeding shear stress
limits.
Express your answer with appropriate units to three significant figures.
A rotating shaft can be used to transmit mechanical
power from one place to another. For example, a
shaft can be connected to a motor at one end and a
• View Available Hint(s)
pulley at the other. The shaft can then transmit
power from the motor to the pulley. When the
machine is operating, the shaft will rotate at some
angular velocity w and will be subject to a torque
T. The power transmitted by the shaft is P = Tw.
HẢ
?
P= 38110.711
Hp
The shaft's rotation can also be expressed as a
frequency, f, which represents the number of
revolutions of the shaft per unit time. The frequency
and angular velocity are related by w = 2nf, so
the power can also be calculated using
P=2nƒT.
Submit
Previous Answers
X Incorrect; Try Again; 9 attempts remaining
When designing a shaft, one consideration is limits
Tc
on shear stress. The torsion formula Tallow =
J
relates the allowable shear stress in a circular shaft
Part B - Minimum diameter
with outer radius c to the torque T. The polar
moment of inertia is J= c for a solid shaft.
2
A solid circular shaft is required to transmit P = 43 kW from a motor to a machine. The maximum allowable stress in the shaft is Tallow = 75 MPa. If the
machine runs at w = 16 rad/s. what is the minimum diameter for the shaft?
In the SI system, the units of torque are newton-
meters (N · m), and the units of power are watts (
1 W=1N. m/s). In the FPS system, the basic
units of torque are foot-pounds (ft - lb), and the
units of power are foot-pounds per second (
ft - lb/s). However, power is often expressed in
horsepower, where 1 hp = 550 ft - lb/s.
Express your answer in cm to three significant figures.
• View Available Hint(s)
D= 5.67 cm
Transcribed Image Text:Power Transmission 4 of 10 > I Review Part A - Transmitted power Learning Goal: To determine the maximum possible power A solid circular rod is used to transmit power from a motor to a machine. The diameter of the rod is D = 2.25 in and the machine operates at w = 120 rpm If the allowable shear stress in the shaft is 12 ksi , what is the maximum power transmissible to the machine? transmission for a circular shaft and the minimum diameter required to avoid exceeding shear stress limits. Express your answer with appropriate units to three significant figures. A rotating shaft can be used to transmit mechanical power from one place to another. For example, a shaft can be connected to a motor at one end and a • View Available Hint(s) pulley at the other. The shaft can then transmit power from the motor to the pulley. When the machine is operating, the shaft will rotate at some angular velocity w and will be subject to a torque T. The power transmitted by the shaft is P = Tw. HẢ ? P= 38110.711 Hp The shaft's rotation can also be expressed as a frequency, f, which represents the number of revolutions of the shaft per unit time. The frequency and angular velocity are related by w = 2nf, so the power can also be calculated using P=2nƒT. Submit Previous Answers X Incorrect; Try Again; 9 attempts remaining When designing a shaft, one consideration is limits Tc on shear stress. The torsion formula Tallow = J relates the allowable shear stress in a circular shaft Part B - Minimum diameter with outer radius c to the torque T. The polar moment of inertia is J= c for a solid shaft. 2 A solid circular shaft is required to transmit P = 43 kW from a motor to a machine. The maximum allowable stress in the shaft is Tallow = 75 MPa. If the machine runs at w = 16 rad/s. what is the minimum diameter for the shaft? In the SI system, the units of torque are newton- meters (N · m), and the units of power are watts ( 1 W=1N. m/s). In the FPS system, the basic units of torque are foot-pounds (ft - lb), and the units of power are foot-pounds per second ( ft - lb/s). However, power is often expressed in horsepower, where 1 hp = 550 ft - lb/s. Express your answer in cm to three significant figures. • View Available Hint(s) D= 5.67 cm
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