resultant Vector

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter11: Angular Momentum
Section: Chapter Questions
Problem 11.4OQ: Let the four compass directions north, east, south, and west be represented by unit vectors ne . ....
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Add the vectors and determine the resultant Vector A=22 m, north Vector B=33 m, West
### Vector Addition and Resultant Determination

**Exercise:**

Add the following component vectors and determine the resultant. (You might want to draw them).

- **Vector A**: 22 m, north
- **Vector B**: 33 m, west

**Options:**

1. 7.4 m, 56 degrees north of east
2. 40 m, 56 degrees west of north
3. 7.4 m, 34 degrees west of north
4. 40 m, 34 degrees west of north

**Explanation:**

To solve this problem, you can use graphical vector addition or the component method to determine the resultant vector. In graphical addition, you would draw vector A pointing north and vector B pointing west. The resultant vector will be the diagonal of the rectangle that these two vectors form, originating from the starting point of vector A and B.

However, for the component method, you need to break down each vector into its respective components and then add those components to find the resultant vector.

1. **North and South Direction**:
   - Vector A: 22 m north.
   - Vector B has no north/south component.

2. **East and West Direction**:
   - Vector A has no east/west component.
   - Vector B: 33 m west.

Once you have these components, you can determine the magnitude and direction of the resultant vector using the Pythagorean theorem and trigonometric functions.

The correct resultant will be given by:

\[ R = \sqrt{(22^2 + 33^2)} \approx 40 \, \text{m}\]

The angle the resultant makes with the north direction can be found using trigonometry:

\[ \theta = \tan^{-1}\left(\frac{33}{22}\right) \approx 56^\circ \]

Thus, the resultant vector is approximately 40 m, 56 degrees west of north, which corresponds to the second option:

- **40 m, 56 degrees west of north**

This is the solution to the problem based on the given component vectors.
Transcribed Image Text:### Vector Addition and Resultant Determination **Exercise:** Add the following component vectors and determine the resultant. (You might want to draw them). - **Vector A**: 22 m, north - **Vector B**: 33 m, west **Options:** 1. 7.4 m, 56 degrees north of east 2. 40 m, 56 degrees west of north 3. 7.4 m, 34 degrees west of north 4. 40 m, 34 degrees west of north **Explanation:** To solve this problem, you can use graphical vector addition or the component method to determine the resultant vector. In graphical addition, you would draw vector A pointing north and vector B pointing west. The resultant vector will be the diagonal of the rectangle that these two vectors form, originating from the starting point of vector A and B. However, for the component method, you need to break down each vector into its respective components and then add those components to find the resultant vector. 1. **North and South Direction**: - Vector A: 22 m north. - Vector B has no north/south component. 2. **East and West Direction**: - Vector A has no east/west component. - Vector B: 33 m west. Once you have these components, you can determine the magnitude and direction of the resultant vector using the Pythagorean theorem and trigonometric functions. The correct resultant will be given by: \[ R = \sqrt{(22^2 + 33^2)} \approx 40 \, \text{m}\] The angle the resultant makes with the north direction can be found using trigonometry: \[ \theta = \tan^{-1}\left(\frac{33}{22}\right) \approx 56^\circ \] Thus, the resultant vector is approximately 40 m, 56 degrees west of north, which corresponds to the second option: - **40 m, 56 degrees west of north** This is the solution to the problem based on the given component vectors.
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