A vector has an x-component of -23.0 units and a y-component of 28.5 units. Find the magnitude and direction of the vector. magnitude units direction • (counterclockwise from the +x-axis)

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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### Vector Magnitude and Direction Calculation

A vector has an x-component of **−23.0 units** and a y-component of **28.5 units**. Find the magnitude and direction of the vector.

- **Magnitude:** _______ units
- **Direction:** _______° (counterclockwise from the +x-axis)

To solve this problem, you can use the following formulas:

1. **Magnitude of the vector** is given by:
   \[
   \text{Magnitude} = \sqrt{(x^2 + y^2)}
   \]

2. **Direction of the vector** (θ), measured counterclockwise from the positive x-axis, can be calculated using:
   \[
   \theta = \tan^{-1}\left(\frac{y}{x}\right)
   \] 

Note: When calculating the direction, consider the signs of x and y to determine the correct quadrant for θ.
Transcribed Image Text:### Vector Magnitude and Direction Calculation A vector has an x-component of **−23.0 units** and a y-component of **28.5 units**. Find the magnitude and direction of the vector. - **Magnitude:** _______ units - **Direction:** _______° (counterclockwise from the +x-axis) To solve this problem, you can use the following formulas: 1. **Magnitude of the vector** is given by: \[ \text{Magnitude} = \sqrt{(x^2 + y^2)} \] 2. **Direction of the vector** (θ), measured counterclockwise from the positive x-axis, can be calculated using: \[ \theta = \tan^{-1}\left(\frac{y}{x}\right) \] Note: When calculating the direction, consider the signs of x and y to determine the correct quadrant for θ.
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The vectors 

Ax=-23.0 unitsAy=28.5 units

 

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