Result For every positive integer n, Proof We proceed by induction. Since We show that (2.1)! 2 2¹.1! 2' the statement is true for n = 1. Assume, for a positive integer k, that 1.3.5... (2k-1)= Observe that (2k + 2)! 2k+1. (k+1)! 1.3.5 (2n − 1) = = 1= 1.3.5...(2k + 1) = (2k + 2)(2k + 1) 2. (k+1) = 1 · 3 · 5 · · · (2k + 1). By the Principle of Mathematical Induction, for every positive integer n. = (2k)! 2k. (k)! (2n)! 2n.n! (2k + 2)! 2k+1. (k+1)! (2k)! 2k. k! 1.3.5... (2n-1) = = (2k + 1)[1 · 3 · 5 · · · (2k − 1)] (2n)! 2n.n!
Result For every positive integer n, Proof We proceed by induction. Since We show that (2.1)! 2 2¹.1! 2' the statement is true for n = 1. Assume, for a positive integer k, that 1.3.5... (2k-1)= Observe that (2k + 2)! 2k+1. (k+1)! 1.3.5 (2n − 1) = = 1= 1.3.5...(2k + 1) = (2k + 2)(2k + 1) 2. (k+1) = 1 · 3 · 5 · · · (2k + 1). By the Principle of Mathematical Induction, for every positive integer n. = (2k)! 2k. (k)! (2n)! 2n.n! (2k + 2)! 2k+1. (k+1)! (2k)! 2k. k! 1.3.5... (2n-1) = = (2k + 1)[1 · 3 · 5 · · · (2k − 1)] (2n)! 2n.n!
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Show the following proof in more detail, please. Especially the yellow highlighted part goes way too fast for me, is there a certain plan/steps I can keep in mind to follow when approaching similar questions?
![Result
For every positive integer n,
Proof We proceed by induction. Since
We show that
(2.1)! 2
2¹.1! 2
the statement is true for n = 1. Assume, for a positive integer k, that
Observe that
1.3.5... (2n-1)=
(2k + 2)!
2k+1. (k+1)!
1 =
for every positive integer n.
1.3.5... (2k + 1) =
1.3.5 (2k − 1) =
(2k + 2)(2k + 1)
2. (k+1)
= 1.3.5... (2k + 1).
By the Principle of Mathematical Induction,
=
(2k)!
2k. (k)!
(2n)!
2n.n!
(2k + 2)!
2k+1. (k+ 1)!*
1.3.5... (2n-1)=
(2k)!
2k. k!
(2k + 1)[1 · 3 · 5 · · · (2k − 1)]
(2n)!
2n.n!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e237d3f-b8e6-4775-a6f9-5671b153aef2%2F7fd79fdd-9242-49a0-b57a-d73b2b2a2ef9%2F0a72hqr_processed.png&w=3840&q=75)
Transcribed Image Text:Result
For every positive integer n,
Proof We proceed by induction. Since
We show that
(2.1)! 2
2¹.1! 2
the statement is true for n = 1. Assume, for a positive integer k, that
Observe that
1.3.5... (2n-1)=
(2k + 2)!
2k+1. (k+1)!
1 =
for every positive integer n.
1.3.5... (2k + 1) =
1.3.5 (2k − 1) =
(2k + 2)(2k + 1)
2. (k+1)
= 1.3.5... (2k + 1).
By the Principle of Mathematical Induction,
=
(2k)!
2k. (k)!
(2n)!
2n.n!
(2k + 2)!
2k+1. (k+ 1)!*
1.3.5... (2n-1)=
(2k)!
2k. k!
(2k + 1)[1 · 3 · 5 · · · (2k − 1)]
(2n)!
2n.n!
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