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4. Use the product rule twice to prove that if f, g,h are differentiable, then (fgh)' = f'gh + fg'h + f gh'. Then taking f = g = h, show that: f (æ)]³ = 3[f(x)]J²f"(x) Then, use this result you just showed to differentiate y = (x² + 3x3 + 17x + 82)3

4. Use the product rule twice to prove that if f, g,h are differentiable, then (fgh)' = f'gh + fg'h + f gh'. Then taking f = g = h, show that: f (æ)]³ = 3[f(x)]J²f"(x) Then, use this result you just showed to differentiate y = (x² + 3x3 + 17x + 82)3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4. Use the product rule twice to prove that if f, g, h are differentiable, then (fgh)' = f'gh + fg'h + fgh'. Then taking f = g = h, show that: d [f(x)]³ = 3[f(x)]²f'(x) dx Then, use this result you just showed to differentiate y = (x* + 3.x3 + 17x + 82)3
Transcribed Image Text:4. Use the product rule twice to prove that if f, g, h are differentiable, then (fgh)' = f'gh + fg'h + fgh'. Then taking f = g = h, show that: d [f(x)]³ = 3[f(x)]²f'(x) dx Then, use this result you just showed to differentiate y = (x* + 3.x3 + 17x + 82)3
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