4. Use the product rule twice to prove that if f, g,h are differentiable, then (fgh)' = f'gh + fg'h + f gh'. Then taking f = g = h, show that: f (æ)]³ = 3[f(x)]J²f"(x) Then, use this result you just showed to differentiate y = (x² + 3x3 + 17x + 82)3

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