MA RA 20 kN ↓ 20 kN ↓ KAB = 10.67x10⁹ -3 m3 m3 m MB . 60 kN RB KBC = 9x10⁹ ←4mm- 4 m a. Construct the Moment distribution table of the beam loaded as shown. b. Based on the table, determine the values of M₁, MB and Mc in KN.m c. Solve for the Reactions at A, B and C (RA Rg and Rc in KN) (Note: Solve first the values of RA and Rc, then solve RB using Fy=0 Rc Mc
MA RA 20 kN ↓ 20 kN ↓ KAB = 10.67x10⁹ -3 m3 m3 m MB . 60 kN RB KBC = 9x10⁹ ←4mm- 4 m a. Construct the Moment distribution table of the beam loaded as shown. b. Based on the table, determine the values of M₁, MB and Mc in KN.m c. Solve for the Reactions at A, B and C (RA Rg and Rc in KN) (Note: Solve first the values of RA and Rc, then solve RB using Fy=0 Rc Mc
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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UPVOTE WILL BE GIVEN (Please write the complete solutions legibly. No long explanation needed. Solve in 4 decimal places and box the final answer.)
![MA
RA
20 kN
↓
20 kN
↓
KAB = 10.67x10⁹
-3 m3 m3 m
MB
.
60 kN
RB
KBC = 9x10⁹
←4mm-
4 m
a. Construct the Moment distribution table of the beam loaded as shown.
b. Based on the table, determine the values of M₁, MB and Mc in KN.m
c. Solve for the Reactions at A, B and C (RA Rg and Rc in KN)
(Note: Solve first the values of RA and Rc, then solve RB using Fy=0
Rc
Mc](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F056d53dc-3f4d-4ce6-b212-dcc4942aa42d%2F74e3b0bc-755a-45b9-a365-a059bfee7356%2F6ngf359_processed.png&w=3840&q=75)
Transcribed Image Text:MA
RA
20 kN
↓
20 kN
↓
KAB = 10.67x10⁹
-3 m3 m3 m
MB
.
60 kN
RB
KBC = 9x10⁹
←4mm-
4 m
a. Construct the Moment distribution table of the beam loaded as shown.
b. Based on the table, determine the values of M₁, MB and Mc in KN.m
c. Solve for the Reactions at A, B and C (RA Rg and Rc in KN)
(Note: Solve first the values of RA and Rc, then solve RB using Fy=0
Rc
Mc
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