The length of a belt in an open-belt drive, L, is given by: where and L = √4c² −(D−d)² + ¹/{D®₂ +ªº₂} 8p=7+2sin-¹ D-d 2c 8₂-7-2 sin-¹ (D-d).

Structural Analysis
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Chapter2: Loads On Structures
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NUMERICAL SOLUTIONS (Methods in solving Non-linear equations.)

 

UPVOTE WILL BE GIVEN. Please write the complete solutions legibly and completely. No long explanation needed. Answer in 2 decimal places. 

 

The length of a belt in an open-belt drive, L, is given by:
where
and
L = √4c²-(D-d)² + ¹/{D÷₂+d²₂}
8p=7+2sin-¹ D-d
2c
8₁ = π-2 sin-¹
D-d
2c
Transcribed Image Text:The length of a belt in an open-belt drive, L, is given by: where and L = √4c²-(D-d)² + ¹/{D÷₂+d²₂} 8p=7+2sin-¹ D-d 2c 8₁ = π-2 sin-¹ D-d 2c
c is the center distance, D is the diameter of the larger pulley, d is the diameter
of the smaller pulley, D is the angle of contact of the belt with the larger pulley,
and ed is the angle of contact of contact of the belt with the smaller pulley.
DI
Figure 1. Open belt drive.
If the belt having a length 11m is used to connect the two pulleys with diameters
0.4m and 0.2m, determine the center distance between the pulleys using
Newton-Raphson Method. Terminate the computation when Za < 0.0005%.
Transcribed Image Text:c is the center distance, D is the diameter of the larger pulley, d is the diameter of the smaller pulley, D is the angle of contact of the belt with the larger pulley, and ed is the angle of contact of contact of the belt with the smaller pulley. DI Figure 1. Open belt drive. If the belt having a length 11m is used to connect the two pulleys with diameters 0.4m and 0.2m, determine the center distance between the pulleys using Newton-Raphson Method. Terminate the computation when Za < 0.0005%.
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