Resistor 10 Q Resistor 51 Q Light bulb (first 3 pts) Light bulb (last 10 pts) Slope (V/A) 9.896V/A 50.91V/A 5.386V/A 43.26V/A Y-intercept (V) 0.0005526V 0.01030V
Resistor 10 Q Resistor 51 Q Light bulb (first 3 pts) Light bulb (last 10 pts) Slope (V/A) 9.896V/A 50.91V/A 5.386V/A 43.26V/A Y-intercept (V) 0.0005526V 0.01030V
Related questions
Question
Do the resistors follow Ohm’s law? Base your answer on the experimental data.
Transcribed Image Text:Resistor 10 Q
Resistor 51 Q
Light bulb (first 3 pts)
Light bulb (last 10 pts)
Slope (V/A)
9.896V/A
50.91V/A
5.386V/A
43.26V/A
Y-intercept (V)
0.0005526V
0.01030V
Transcribed Image Text:6
2
0
0.0
6
2
X
Linear Fit for: Latest | Potential
Pot = ml+b
m (Slope): 50.91 V/A
b (Y-Intercept): 0.01030 V
Correlation: 1.000
RMSE: 0.009341 V
Linear Fit for: Run 2 | Potential
Pot = ml+b
m (Slope): 50.91 V/A
b (Y-Intercept): 0.01030 V
Correlation: 1.000
RMSE: 0.009341 V
0
0.0
(AI:0.0210 Ay:0.000)
Correlation: 0.9970
RMSE: 0.008877 V
Linear Fit for: Run 1 | Potential
Pot ml+b
m (Slope): 9.896 V/A
b (Y-Intercept): 0.0005526 V
Correlation: 1.000
RMSE: 0.002877 V
Linear Fit for: Latest | Potential
Pot = ml+b
m (Slope): 43.26 V/A
b (Y-Intercept): -2.512 V
Linear Fit for: Latest | Potential
Pot = ml+b
m (Slope): 5.386 V/A
b (Y-Intercept): -0.002003 V
Correlation: 0.9988
RMSE: 0.01541 V
-
0.2
0.2
Current (A)
Ohm's Law
Linear Fit for: Run 1 | Potential
Pot = ml+b
m (Slope): 9.896 V/A
b (Y-Intercept): 0.0005526 V
Correlation: 1.000
RMSE: 0.002877 V
Current (A)
0.4
0.4
Expert Solution
Step 1
Ohms law is given by the equation
where V is the voltage, I is the current and R is the resistance.
If we plot V along the Y axis and R along the X axis, then we would get a straight line which will have a slope equal to I (current) and 0 intercept.
Step by step
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