Researchers studying the effects of diet on growth would like to know if a vegetarian diet affects the height of a child. The researchers randomly selected 11 vegetarianchildren that were six years old. The average height of the children is 42.5 inches with a standard deviation of 4.1 inches. The average height for all six-year-old childrenis 45.75 inches, Using confidence intervals, test to determine whether there is overwhelming evidence at a 0.10 that six-year-old vegetarian children are not the sameheight as other six-year-old children. Assume the population is normally distributedStep 1 of 2: Calculate a confidence interval for the average height of six-year-old vegetarian children. Round your answers to two decimal places.

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Answered: Researchers studying the effects of…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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The principal at a large high school claims that students spend at least 10 hours per week doing homework, on average. To investigate this claim, an AP Statistics class selected a random sample of 250 students from their school and asked them how long they spent doing homework during the last week. The sample mean was 10.2 hours and the sample standard deviation was 4.2 hours. Construct and interpret a 95% confidence interval for the mean time that students at this school spent doing homework in the last week. Based on your interval, what can you conclude about the principal's claim? What is your t* value? Remember to use the conservative DF value.
Nielsen Media Research conducted a study of household television viewing time during the 7PM to 10PM time period (This is known as Prime Time). The average weekly time spent watching was 785 minutes. This was based off 600 randomly selected households. Based upon past studies the population standard deviation is known to be 65 minutes. Develop an 80% confidence interval for the average time Americans watched prime-time TV this week.
You measure 25 randomly selected textbooks' weights, and find they have a mean weight of 73 ounces. Assume the population standard deviation is 5.8 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight.
People who diet can expect to lose an average of 2 kg in a month. In a book, the authors claim that people who follow a new diet will lose an average of more than 2 kg in a month. The weight losses of the 18 people in a random sample who had followed the new diet for a month were noted. The sample mean was 2.1 kg and the standard deviation was 0.5 kg. Test the authors’ claim at the 5% significance level
A new drug is being tested to see if it reduces the frequency of migraines. Study participants were divided into two groups. 49 participants in group 1 received the medication; 42 participants in group 2 received a placebo. After a period of six months, group 1 had a mean of 4 migraines. It is known that the population standard deviation for this group is 1.3 migraines. Group 2 had a mean of 5.4 migraines. The population standard deviation for this group is 1.7 migraines. Can we conclude that the medication reduces the population mean number of migraines? Use αα =0.01. Note: If t-test, then unequal variances are assumed. Question a)Let: μ1μ1 = the population mean number of migraines with the medication μ2μ2 = the population mean number of migraines with the placebo (Step 1) State the null and alternative hypotheses by selecting the appropriate symbol, and identify which tailed test: H0:H0: μ1μ1 μ2μ2 H1:H1: μ1μ1 μ2μ2 Which tailed test…
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Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
a group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. what is the 90% confidence interval for the mean score, u, of all students taking the test?
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