Required information Two wooden crates with masses as shown are tied together by a horizontal cord. Another cord is tied to the first crate. and it is pulled with a force of 195 N at an angle of 20.0°, as shown. Each crate has a coefficient of kinetic friction of 0.480. 140 kg 25.0 kg

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question

can you check this practice question, can you show me how to do it please.

### Understanding Tension in a Rope Connecting Two Crates

#### Problem Description:
Two wooden crates of masses 14.0 kg and 25.0 kg are interconnected by a horizontal cord. A second cord is attached to the first crate, and a pulling force of 195 N is applied at an angle of 20.0° above the horizontal. Each crate experiences frictional resistance characterized by a coefficient of kinetic friction of 0.480. 

#### Diagram Interpretation:
- **Crates and Masses**:
  - The left crate has a mass of 14.0 kg.
  - The right crate has a mass of 25.0 kg.
- **Pulling Force**:
  - A force of 195 N is applied to the first crate at an angle of 20.0° from the horizontal, represented by an arrow pointing upwards and to the right.
  
#### Objective:
- Determine the tension in the rope that connects the two crates.

#### Given Data:
- Mass of first crate: 14.0 kg
- Mass of second crate: 25.0 kg
- Applied force: 195 N at 20.0° angle
- Coefficient of kinetic friction for both crates: 0.480
- Tension in the rope connecting the crates is calculated to be 11.298 N

By applying concepts of Newton’s laws of motion, frictional force, and vector decomposition, the problem involves calculating the horizontal and vertical components of forces, accounting for friction, and solving for the tension in the connecting rope. 

This problem can typically be approached by:
1. Drawing free body diagrams for each crate.
2. Breaking down the forces into components.
3. Applying Newton's second law in the horizontal and vertical directions.
4. Summing up the forces to find the net tension in the rope. 

Complete solutions require detailed understanding of physics principles and mathematical competence in solving simultaneous equations derived from Newton’s laws.

For reference, the correct tension in the rope connecting the two crates as per the solution is:

**Tension**: 11.298 N
Transcribed Image Text:### Understanding Tension in a Rope Connecting Two Crates #### Problem Description: Two wooden crates of masses 14.0 kg and 25.0 kg are interconnected by a horizontal cord. A second cord is attached to the first crate, and a pulling force of 195 N is applied at an angle of 20.0° above the horizontal. Each crate experiences frictional resistance characterized by a coefficient of kinetic friction of 0.480. #### Diagram Interpretation: - **Crates and Masses**: - The left crate has a mass of 14.0 kg. - The right crate has a mass of 25.0 kg. - **Pulling Force**: - A force of 195 N is applied to the first crate at an angle of 20.0° from the horizontal, represented by an arrow pointing upwards and to the right. #### Objective: - Determine the tension in the rope that connects the two crates. #### Given Data: - Mass of first crate: 14.0 kg - Mass of second crate: 25.0 kg - Applied force: 195 N at 20.0° angle - Coefficient of kinetic friction for both crates: 0.480 - Tension in the rope connecting the crates is calculated to be 11.298 N By applying concepts of Newton’s laws of motion, frictional force, and vector decomposition, the problem involves calculating the horizontal and vertical components of forces, accounting for friction, and solving for the tension in the connecting rope. This problem can typically be approached by: 1. Drawing free body diagrams for each crate. 2. Breaking down the forces into components. 3. Applying Newton's second law in the horizontal and vertical directions. 4. Summing up the forces to find the net tension in the rope. Complete solutions require detailed understanding of physics principles and mathematical competence in solving simultaneous equations derived from Newton’s laws. For reference, the correct tension in the rope connecting the two crates as per the solution is: **Tension**: 11.298 N
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Household circuits
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON