Question 136 to 139 **Physics Problems on Momentum and Force****137.** What is the magnitude of the velocity of a 25-kilogram object that has a momentum of 100 kilogram meters per second?Options: (1) 0.25 m/s (2) 2500 m/s (3) 40. m/s (4) 4.0 m/s**138.** What is the momentum of a 1,200-kilogram car traveling at 15 meters per second due east?Options: (1) 80. kg·m/s due east (2) 80. kg·m/s due west (3) 1.8 x 10^4 kg·m/s due east (4) 1.8 x 10^4 kg·m/s due west**139.** A constant unbalanced force acts on an object for 3.0 seconds, producing an impulse of 6.0 newton-seconds east. Determine the magnitude and direction of the force.**140.** A 10-newton force acts on an object for 0.010 second. What force, acting on the object for 0.050 second, would produce the same impulse?Options: (1) 1.0 N (2) 2.0 N (3) 5.0 N (4) 10. N**141.** What is the magnitude of the net force acting on a 2.0 x 10^3-kilogram car as it accelerates from rest to a speed of 15 meters per second in 5.0 seconds?Options: (1) 6.0 x 10^3 N (2) 2.0 x 10^4 N (3) 3.0 x 10^4 N (4) 6.0 x 10^4 N**142.** A 5.00-kilogram mass is traveling at 100. meters per second. Determine the speed of the mass after receiving an impulse of 50.0 N·s. The image contains a physics problem followed by a review question:---**Problem Solution:**\[ v_{Bf} = \frac{(1.0 \, \text{kg})(0.0 \, \text{m/s}) + (0.20 \, \text{kg})(10.0 \, \text{m/s}) - (1.0 \, \text{kg})(3.0 \, \text{m/s})}{0.20 \, \text{kg}} \]\[ v_{Bf} = -5.0 \, \text{m/s} \]The velocity of cart B after the collision is 5.0 m/s to the left.---**Review Questions:**136. As an object falls freely toward Earth, the object's momentum: - (1) decreases - (2) increases - (3) remains the same

Answered: Image /qna-images/answer/8fdf9705-6449-45ba-b5b6-cb98e869b1c2.jpg

Answered: 137. What is the magnitude of the…

137. What is the magnitude of the velöčity öf å 25-kilogram object that has a momentum of 100.kilogram meters per second? (1) 0.25 m/s (2) 2500 m/s (3) 40. m/s (4) 4.0 m/s

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter22: Electric Current

Section: Chapter Questions

Problem 84A

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Question

Question 136 to 139

**Physics Problems on Momentum and Force**

**137.** What is the magnitude of the velocity of a 25-kilogram object that has a momentum of 100 kilogram meters per second?

Options:
(1) 0.25 m/s
(2) 2500 m/s
(3) 40. m/s
(4) 4.0 m/s

**138.** What is the momentum of a 1,200-kilogram car traveling at 15 meters per second due east?

Options:
(1) 80. kg·m/s due east
(2) 80. kg·m/s due west
(3) 1.8 x 10^4 kg·m/s due east
(4) 1.8 x 10^4 kg·m/s due west

**139.** A constant unbalanced force acts on an object for 3.0 seconds, producing an impulse of 6.0 newton-seconds east. Determine the magnitude and direction of the force.

**140.** A 10-newton force acts on an object for 0.010 second. What force, acting on the object for 0.050 second, would produce the same impulse?

Options:
(1) 1.0 N
(2) 2.0 N
(3) 5.0 N
(4) 10. N

**141.** What is the magnitude of the net force acting on a 2.0 x 10^3-kilogram car as it accelerates from rest to a speed of 15 meters per second in 5.0 seconds?

Options:
(1) 6.0 x 10^3 N
(2) 2.0 x 10^4 N
(3) 3.0 x 10^4 N
(4) 6.0 x 10^4 N

**142.** A 5.00-kilogram mass is traveling at 100. meters per second. Determine the speed of the mass after receiving an impulse of 50.0 N·s.

The image contains a physics problem followed by a review question:

---

**Problem Solution:**

\[ v_{Bf} = \frac{(1.0 \, \text{kg})(0.0 \, \text{m/s}) + (0.20 \, \text{kg})(10.0 \, \text{m/s}) - (1.0 \, \text{kg})(3.0 \, \text{m/s})}{0.20 \, \text{kg}} \]

\[ v_{Bf} = -5.0 \, \text{m/s} \]

The velocity of cart B after the collision is 5.0 m/s to the left.

---

**Review Questions:**

136. As an object falls freely toward Earth, the object's momentum:
- (1) decreases
- (2) increases
- (3) remains the same

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