Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. In the given circuit, Vx = 9 V. 1192 www 41₁ 792 1022 2 A With the assistance of source transformations, transform the voltage sources in the given figure into appropriate current sources. (You must provide an answer before on moving to the next part.) The 9 V voltage source is transformed into a A current source in parallel with the 11 Q2 resistor. The dependent voltage source is (Click to select) ✓

Q: 100V | OA. Series O B. Series-Parallel O C. Parallel O D. Simple

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Q: R4 R2 R3 R12 R6 R5 10 V Rl = 10 n R4 = 100 n R2 = 56 N R5 = 10 n R3 = 10 n R6 = 15 n %3D

A: By using KCL

Q: R3 R, R5 R6 R R7 R4 R3, = R6, = R9 = 50 R2, = R5, = R8 = 42 R1, = R4, = R7 = 20

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A: Step 1:

Q: R2 R1 A B 'VSALIDA R4 R3 13

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Q: 200 mA U 009 U 00 1kM U 08

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.