20Required informationNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in adrawing if 50 people enter a contest and satisfying the following conditions? (Enter the value of probability in decimals.Round the answer to two decimal places.)No one can win more than one prize.Multiple Choice1.60 x 10-71.53 x 10-71.81 x 10-73.96 x 10-7

Permutation is an arrangement of the objects. It is often used in probability theory. According to the classical definition of probability, probability of an event is the ratio of the number of cases favorable to the event to the total number of outcomes. In many occasions, these numbers are calculated using permutation.Let A be the event that Bo, Colleen, Jeff and Rohini win the first, second, third and fourth prizes respectively. Here, the total number of outcomes is the number of ways in which 50 people can be arranged among themselves for 50 prizes which is n=50! Now, Bo, Colleen, Jeff and Rohini can win the first, second, third and fourth prizes respectively in only one way. The remaining 46 people can win 46 prizes in 46! ways. So, the number of cases favorable to the event A is n(A)=1×46! Therefore, the required probability is P(A)=1×46!50!=15527200=1.81×10-7 Answer: The correct answer is: The third option. Therefore, all other options are incorrect.