/** removeDuplicates returns a new array containing the unique values in the array. There should not be any extra space in the array --- there should be exactly one space for each unique element (Hint: numUnique tells you *how big the array should be). You may assume that the list is sorted, as * you did for numUnique. *Your solution may call numUnique, but should not call any other * functions. After the call to numUnique, you must go through the array * exactly one more time. Here are some examples (using "==" informally): * * * * * } new double[] { } == removeDuplicates (new double[] { }) new double[] {11} == removeDuplicates (new double[] {11}) == removeDuplicates (new double[] { 11, 11, 11, 11 }) new double[] { 11, 22, 33, 44, 55, 66, 77, 88 } == removeDuplicates (new double[] { 11, 11, 11, 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88, 88 }) == removeDuplicates (new double[] { 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88 }) * */ public static double [] removeDuplicates (double[] list) { double [] result = new double [numUnique (list)]; // .. return result; // TODO: fix this

/** removeDuplicates returns a new array containing the unique values in the array. There should not be any extra space in the array --- there should be exactly one space for each unique element (Hint: numUnique tells you how big the array should be). You may assume that the list is sorted, as you did for numUnique. Your solution may call numUnique, but should not call any other functions. After the call to numUnique, you must go through the array * exactly one more time. Here are some examples (using "==" informally): * * * * * } new double[] { } == removeDuplicates (new double[] { }) new double[] {11} == removeDuplicates (new double[] {11}) == removeDuplicates (new double[] { 11, 11, 11, 11 }) new double[] { 11, 22, 33, 44, 55, 66, 77, 88 } == removeDuplicates (new double[] { 11, 11, 11, 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88, 88 }) == removeDuplicates (new double[] { 11, 22, 33, 44, 44, 44, 44, 44, 55, 55, 66, 77, 88 }) * */ public static double [] removeDuplicates (double[] list) { double [] result = new double [numUnique (list)]; // .. return result; // TODO: fix this

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Can you help me please: have the program know when numbers out of the array boundaries are received and mitigate those problems. The given code intentionally induces numbers out of bounds and the student’s portion must correct for this. As always use a header file and implementation file to do those calculations. Remember not to change the given code below in any way Design and implement the class myArray that solves the array index out of bounds problem and also allows the user to begin the array index starting at any integer, positive or negative. Every object of type myArray is an array of type int. During execution, when accessing an array component, if the index is out of bounds, the program must terminate with an appropriate error message. Consider the following statements:myArray list(5);                                  //Line 1 myArraymyList(2, 13);                     //Line 2myArray yourList(-5, 9);                    //Line 3The statement in Line 1 declares list to be an…
Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int oldScores[4]). Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int SCORES_SIZE = 4; int oldScores[SCORES_SIZE]; int newScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> oldScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout << newScores[i] << " "; } cout…
Question 19 a Consider the following statement, which is intended to create an ArrayList named years that can be used to store elements both of type Integer and of type String. /* missing code */ = new ArrayList(); Which of the following can be used to replace /* missing code */ so that the statement compiles without error? ArrayList years B ArrayList years() ArrayList years[] D ArrayList years E ArrayList years
Write a function template that gets an array of generic type T as well as the number of items within the array, calculates the standard deviation of the items within the array and returns it. The user will first give an integerItemCount value (int) and that many integer values (all ints). Then, the user will give a doubleItemCount value (int) and that many double values (all doubles). Then, the program will use the function template to calculate the standard deviations of both arrays and print them out as first the standard deviation of the int array, then the standard deviation of the double array. Standard deviation of an array with size N, values are given as , and arithmetic mean as μ can be calculated as: Requirements: You MUST define and use a function template that takes an array of generic type T and an integer which defines the size of the array Getting all the user input, calling the appropriate version of the function via the template and printing the output should be done…
In the following code both myList and yourList are dynamic arrays of the same size. The code initializes the array myList to certain values. The value in each element of yourList should be twice the value in the corresponding element in myList. However, the output of this code would show that is not the case. Provide the correct code to accomplish the desired results. int *myList;int *yourList;myList = new int[5];myList[0] = 8;for (int i = 1; i < 5; i++)myList[i] = i * myList[i - 1];yourList = myList;for (int i = 0; i < 5; i++)yourList[i] = 2 * myList[i];
1. Declare an array to hold eight integers. Use a for loop to add eight random integers, all in the range from 50 to 100, inclusive, to this array. Duplicates are okay. Next, pass the array to a method that sorts the array and returns another array containing only the largest and smallest elements in the original array. Print these two values in main. Then use a foreach loop to display all elements of the sorted array on one line separated by a single space. This latter loop should also count the odd and even numbers in the array and determine the sum of all elements in the array. SAMPLE OUTPUT The lowest element is 59 The highest element is 96 Here is the array 59 64 76 77 80 88 91 96 Evens: 5, odds: 3 Total: 631
If an array is given, identify the next bigger element for each element in the array, if one exists. If the element is not accessible, print the element itself. The next bigger element y in the array for an element x is the first element that is greater than x and appears on its right side. The element itself is the next bigger member of the array's rightmost element. Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]. use python to code
Determine if the following statements is true or false. Screen shot shows the text's arraycollection and sortedarraycollection With the text's array-based collection implementation, the set of stored elements is scattered about the array. The text's sorted array-based collection implementation stores elements in the lowest possible indices of the array. When comparing two objects using the equals method inherited from the Object class, what is actually compared is the contents of the objects.
] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Python
Which of the following statements regarding linked lists and arrays is correct? Group of answer choices: a. A dynamically resizable array makes insertions at the beginning of an array very efficient. b. Using a doubly linked list is more efficient than an array when accessing the ith element of a structure. c. A dynamically resizable array is another name for a linked list. d. Any type of list tends to be better than an array when there are a set number of maximum items known beforehand. e. If many deletions at any place in the structure were common, a linked list implementation would likely be preferable to an array
Which of the following are true about arrays? Arrays are reference types. Array indexing is bounds‐checked. Arrays sometimes can be created without using new. The entire contents of an array can be copied via =.
PART A. We will start by finding the largest value. Initially, we assume that the first element in the list is the largest element and create a variable maxValue that is initialized to the first element in the array. We then compare the element that maxValue is storing with every element in the list. Whenever we find an element in the array larger than the element that maxValue is storing, we update maxValue so that it stores the value of the newer larger element. Algorithm ArrayLargestElement Declare and initialize maxValue to the first element in the array. Use a FOR loop to traverse the array. // You already checked the first element, so you should start the loop at the second element. If the element at this index is larger than maxValue Update maxValue Output maxValue. Write a program MyArray_ABC that declares an array containing the following elements: 45, 38, 27, 46, 81, 72, 56, 61, 20, 48, 76, 91, 57, 35, and 78, and outputs the largest value. Additionally,…