Relative abundance Mass Spectroscopy 195 compound (A). 100 CH;CHCH3 43 Č! 50 41 63 78 65 80 eadem ol gl 100 llod 10 20 30 40 50 60 70 80 90 a bauoqmo miz Fig. 4.16
Relative abundance Mass Spectroscopy 195 compound (A). 100 CH;CHCH3 43 Č! 50 41 63 78 65 80 eadem ol gl 100 llod 10 20 30 40 50 60 70 80 90 a bauoqmo miz Fig. 4.16
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
( do 19 with explanation
Transcribed Image Text:4.20. SOLI
No par
1.
alkane
becaus
(no M')
30 4
50
60
70
80
90
100
110
120
130 140
m/z
Fig. 4.14
17. (a) Explain how to detect the presence of (i) Br (ii) Cl and (III) I in a molecule CH
mass spectrometry
| 43
| CH;CH,CH,Br
80
(b) Give the relative
60
spectrum
of
40
41
20-
Deduce
15
the
of
10 20
80 90 100 110
the
30
40
50
60
70
miz
Fig. 4.15
O Scanned with Oken Scanner
Relative abundance
レマ
డి
O Scanned with Oken Scanner
4/4
Mass Spectroscopy
195
compound (A).
100
43
CH;CHCH;
Č!
50
Tat bro
eb a
41
63
78
65
80
de ager e'ello 0
bdsbis n
10
20
30
40
50
60
70
80
90
100
ofoM
Relative abundance
miz
Fig. 4.16
20. Compound (A) C;H120 is an alcohol. It shows prominent peaks at mle = 88 (M*), 55, 42
(base peak), 31 and 29. Give the structure of the compound.
21. Compound (A) C¸H1,O is an alcohol. It does not show molecular ion peak. The peaks shown
by this compound are at mle = 59 (base peak) 41, 29 and 27. What will be the structure of
compound (A) ?
22. Methyl salicylate exhibits peaks at mle = 152 (M*), 121, 120, 92, 65 and 64. Explain the
formation of ions corresponding to these peaks.
4.20. SOLUTIONS.
Relat
1.Jahoin
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