Regression Analysis: Mango Output versus fertilizer and insecticide. Predictor coef SE Coef Constant 75.6752 10.0451 Fertilizer 2.310 1.96 Insecticide 4.2150 2.015 X X 13.1459 R-Sqr = 89.1% R-sgr (Adjusted) = 85.64 whin lysis of Variance rce MS DF SS ression 2 20,200.35 X dual Error 37 140.50 al a) Fill-up the blanks as marked. b) Can you conclude that application of fertilizers have increased mango output significantly at 5% level of significance. c) Construct a 95% confidence interval for Fertilizer coefficient.
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- A multiple regression model has been fit to a data set with p predictor variables, and the adjusted R-squared value is 0.75. What can we conclude about the model fit and the predictor variables in the model?The following regression has been estimated: Dependent Variable: disability 1 Independent Variables: (1) Constant, (2) Person's age (ecage26), (3) male1 "male1" is equal to 1 for males and 0 for females; disability1 is equal to 1 for disabled and 0 for not disabled regress disabilityl ecage26 malel Source | Total | Model | 1137.25995 2 Residual | 9104.04738 47702 disabilityl I ecage26 | malel SS cons df 10241.3073 47704 Coef. Std. Err. .0084218 -.0084567 -.0891858 MS 568.629974 .19085253 .214684457 .0001093 .0040058 .0060068 t 77.04 -2.11 -14.85 47705 Number of obs = F( 2, 47702) = 2979.42 Prob > F R-squared Adj R-squared = Root MSE P>|t| 0.000 0.035 0.000 [95% CI] = = 0.0000 0.1110 0.1110 .43687 .0082076 -.0163082 -.1009592 .0086361 -.0006052 -.0774125 a) Report the estimated values (the actual numbers) of the coefficient estimates (including the constant) and explain what they measure. b) What are some economic reasons why the estimated coefficients might take on the signs (and…Please analyze these tables one by one . Explain as table 1 and table 2.
- In the picture, there is a summary of regression analysis output in the R program. Please comment on the Estimate, Std. Error, t value, Pr(>|t|), F-statistic , P value and Residual standard error.Please see attached image for questionONA model is developed for forecasting of sale and the effects of three independent variables , advertising expenditure (X1), Price (X2), and time (X3) resulted in the following. Regression Statistics Standard Error 232.29 Table 1: ANOVA df SS MS F Regression 3 53184931.86 ? ? Residual ? 1133108.30 ? Total 24 54318040.16 Table 2: regression Coefficients Standard Error t Stat Intercept 927.23 1229.86 ? Advertising (X1) 1.02 3.09 ? Price (X2) 15.61 5.62 ? Time (X3) 170.53 28.18 ? Fill in the blanks in table 1 and table 2 . What is the total number of observations . Write down the…
- The US government is interested in understanding what predicts death rates. They have a set of data that includes the number of deaths in each state, the number of deaths resulting from vehicle accidents (VEHICLE), the number of people dying from diabetes (DIABETES), the number of deaths related to the flu (FLU) and the number of homicide deaths (HOMICIDE). How much variance in deaths is explained by the model’s independent variables?The regression equation for predicting a woman's muscle mass (a quantitative metric, Y) from age (in years, X) is given as ý = 156.35 - 1.19. The ANOVA table for the linear regression of Y vs X is given below. Source Df SS MS p-value Age 11627.5 11627,5 174.06 <,0001 Error 58 3874.4 66.8 Total 59 15501.9 Fill in the blanks below that demonstrate how to construct an interval estimate for the muscle mass of an individual 60-year-old woman. Use a confidence level of 95%; note that the multiplier is t = 2.002 and the standard error of the mean response is s(i,) = 1.055. 95% Interval: ( Select) + ( Select ) [ Select]Simple linear regression results: Dependent Variable: Heart. DiseaseIndependent Variable: BikingHeart. Disease = 18.115809 - 0.20845321 BikingSample size: 68R (correlation coefficient) = -0.94616452R-sq = 0.8952273Estimate of error standard deviation: 1.5273175 Correlation between Biking and Heart. Disease is: -0.94616452. Correlation between Smoking and Heart. Disease is: 0.32421. 1) State r 2 (i.e., the coefficient of determination) for “Biking” and “Heart.Disease” and explain what this value means in context of the data set.
- A sales manager for an advertising agency believes there is a relationship between the number of contacts that a salesperson makes and the amount of sales dollars earned. A regression analysis shows the following results. Coefficients Standard Error t-Stat p-value Intercept -12.201 6.560 -1.860 0.100 Number of contacts 2.195 0.176 12.505 0.000 ANOVA df SS MS F Significance F Regression 1.00 |13,555.42 |13,555.42 156.38 0.00 Residual 8.00 693.48 86.68 Total 9.00 14,248.90 Assume that X = 33.4 and E(X – X) 2814.4. Rounding to one decimal place, the 95% confidence interval for 30 calls isA study was conducted to determine the relationship between starting salaries (RM thousands) for recent statistics graduates and their grade point averages in the major course. A linear regression model was fitted to the data and the estimates regression function was obtained. Part of the computer output for the above analysis is given below: ANOVA Model Sum of df Mean F Sig. Squares Square Regression 147.28 .000 Error 734.9 40.828 Total 6748.2 Coefficients Unstandardized Coefficients Model Sig. Std. B Error Constant GPA -8.42 3.007 3.395 0.2477 -2.48 12.14 0.011 0.000 (a) Complete the ANOVA table (blue boxes). (b) Write down the estimated regression function. Interpret the estimated parameters. (c) Test whether there is a linear association between salaries and grade point average. Use a = 0.05. (d) Determine the coefficient of determination for the model and interpret its meaning.A Bivariate Regression was conducted to evaluate the predictive relationship between total years of schooling and annual income. The results of the regression model were F(1,88) = 4.1, p < .05. What can be concluded about these results? Group of answer choices total years of schooling is a significant predictor of annual income. total years of schooling is not a significant predictor of annual income.