Need asap please help Refrigerant-134a is throttled from the saturated liquid state at 850 kPa to a pressure of 200 kPa. Determinethe temperature drop during this process and the final specific volume of the refrigerant.P₁ = 850 kPaSat. liquid규R-134aP₂ = 200 kPa

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Answered: Refrigerant-134a is throttled from the…

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter8: Engineering Materials

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Refrigerant-134a is throttled from the saturated liquid state at 850 kPa to a pressure of 200 kPa. Determine the temperature drop during this process and the final specific volume of the refrigerant. P₁ = 850 kPa Sat. liquid 규 R-134a P₂ = 200 kPa
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A vapor compression refrigeration cycle uses steam as the working fluid. Steamflows steadily with a mass ow rate of 0.5 kg/s. Saturated vapor at 2.0 o C (State 1) enters an uninsulated compressor and it is compressed to 0.35 bar (State 2). Heat transfer at the rate of 105 kJ/s occurs from the compressor to its surroundings and the heat transfer exactly balances the entropy generation rate so that s2 = s1. The boundary and surrounding temperature of the compressor is measured to be 26.67 o C. Steam exits as saturated liquid at 0.34 bar (State 3) from the condenser. Steam leaving the condenser is then throttled in an expansion valve (State 4) before entering a constant pressure evaporator to complete the thermodynamic cycle. (a) Calculate the power (kJ/s) for the compressor. (b) Determine the isentropic efficiency (%) of the compressor. (c) Calculate the entropy generation for the compressor. (d) Find the coefficient of performance of the refrigeration cycle. (e) Show the cycle on T-s…

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Refrigerant-134a is throttled from the saturated liquid state at 850 kPa to a pressure of 200 kPa. Determine the temperature drop during this process and the final specific volume of the refrigerant. P₁ = 850 kPa Sat. liquid 규 R-134a P₂ = 200 kPa