[References] Use the References to access important values if needed for this question. Consider the following equilibrium system at 512 K. COBr2 (g) CO(g) + Br₂(g) If an equilibrium mixture of the three gases at 512 K contains 1.01 x 10-6 M COBr2, 3.19 x 10-2 M CO, and 2.13 x 10-2 M Br2, what is the value of the equilibrium constant K? K=

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter14: Chemical Equilibrium
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Problem 14.3QE: Describe a nonchemical system that is not in equilibrium, and explain why equilibrium has not been...
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**Equilibrium Constant Calculation**

Consider the following equilibrium system at 512 K:

\[ \text{COBr}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Br}_2 (g) \]

If an equilibrium mixture of the three gases at 512 K contains:
- \(\text{COBr}_2\): 1.01 x 10⁻⁶ M
- \(\text{CO}\): 3.19 x 10⁻² M
- \(\text{Br}_2\): 2.13 x 10⁻² M

What is the value of the equilibrium constant \(K\)?

\[ K = \boxed{\phantom{00}} \]

You have 1 item attempt remaining.

---

In this exercise, you are asked to calculate the equilibrium constant \(K\) for the given chemical reaction using the concentrations of the reactants and products at equilibrium.
Transcribed Image Text:**Equilibrium Constant Calculation** Consider the following equilibrium system at 512 K: \[ \text{COBr}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Br}_2 (g) \] If an equilibrium mixture of the three gases at 512 K contains: - \(\text{COBr}_2\): 1.01 x 10⁻⁶ M - \(\text{CO}\): 3.19 x 10⁻² M - \(\text{Br}_2\): 2.13 x 10⁻² M What is the value of the equilibrium constant \(K\)? \[ K = \boxed{\phantom{00}} \] You have 1 item attempt remaining. --- In this exercise, you are asked to calculate the equilibrium constant \(K\) for the given chemical reaction using the concentrations of the reactants and products at equilibrium.
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