[References] Use the References to access important values if needed for this question. Consider the following reaction where Ke = 9.52x10-² at 350 K: CH4(9) + CCl4(9) ? 2CH₂Cl₂(9) A reaction mixture was found to contain 4.55x10-2 moles of CH4(9), 4.41x102 moles of CCI4(9) and 1.18x10-2 moles of CH₂Cl₂(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 8 1. In order to reach equilibrium CH₂Cl₂(g) must be consumed. B 2. In order to reach equilibrium Ke must decrease. 3. In order to reach equilibrium CH4 must be produced. 84. Qc is less than Ke. 85. The reaction is at equilibrium. No further reaction will occur. Submit Answer Retry Entire Group 9 more group attempts remaining

[References] Use the References to access important values if needed for this question. Consider the following reaction where Ke = 9.52x10-² at 350 K: CH4(9) + CCl4(9) ? 2CH₂Cl₂(9) A reaction mixture was found to contain 4.55x10-2 moles of CH4(9), 4.41x102 moles of CCI4(9) and 1.18x10-2 moles of CH₂Cl₂(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 8 1. In order to reach equilibrium CH₂Cl₂(g) must be consumed. B 2. In order to reach equilibrium Ke must decrease. 3. In order to reach equilibrium CH4 must be produced. 84. Qc is less than Ke. 85. The reaction is at equilibrium. No further reaction will occur. Submit Answer Retry Entire Group 9 more group attempts remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Express the equilibrium constant for the following reaction: 2 CH2CI2 (g) + Cl2 (9) =2 CHCI3 + H2 (g) [CHCI3}[H2] [CHCI,}[Cl,] [CHCI2][CI2] k = [CHCI3][H2] [CHCI3][H2] k = [CHCI,][Cl2] [CHCI,[Cl,] [CHCI3]°[H2] [CHCI3]?{H2] Ok= [CHCI,j!/?{Cl,]
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= [Review Topics] [References] Use the References to access important values if needed for this question. The equilibrium constant, Ke, for the following reaction is 10.5 at 350. K. 2CH₂Cl2 (9) CH4 (9) + CCl4 (9) = Calculate the equilibrium concentrations of reactant and products when 0.315 moles of CH₂Cl2 (g) are introduced into a 1.00 L vessel at 350. K. [CH₂Cl₂] = [CH4] [CC14] = = Submit Answer Show Hint NOV 30 Q F4 M M M Retry Entire Group 9 F5 + tv ♫ 8 9 more group attempts remaining MacBook Air C F6 < F7 DII F8 Previous Email Instructor F9 O Next Save and Exit J F10
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