[References] At a particular temperature a 2.00-L flask at equilibrium contains 5.00 × 10* moles of N2, 2.50 x 10- moles of O2, and 2.00 x 10-2 moles of N, O .Calculate K at this temperature for the reaction 2N2 (g) + O2(g) 2N20(g) K = If (N2] = 2.00 x 10- M, N2O] = 0.200 M, and [02] = 0.00781 M, does this represent a system at equilibrium? Submit Answer Try Another Version 10 item attempts remaining

[References] At a particular temperature a 2.00-L flask at equilibrium contains 5.00 × 10* moles of N2, 2.50 x 10- moles of O2, and 2.00 x 10-2 moles of N, O .Calculate K at this temperature for the reaction 2N2 (g) + O2(g) 2N20(g) K = If (N2] = 2.00 x 10- M, N2O] = 0.200 M, and [02] = 0.00781 M, does this represent a system at equilibrium? Submit Answer Try Another Version 10 item attempts remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the equilibrium system described by the chemical reaction below, which has a value of Kc equal to 1.2 x 104 at a certain temperature. If a solid sample of NH.SH decomposes, what will the equilibrium concentration of NH3 be? NH:SH(s) = NH3(g) + H2S(g) 1 2 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. NH.SH(s) NH:(g) H2S(g) Initial (M) Change (M) Equilibrium (M) RESET 1.2 x 104 +x +2x -2x 1.2 x 104 + x 1.2 x 104 - x 1.2 x 104 + 2x 1.2 x 104- 2x
7. Consider the following equilibrium: 2NOCI(g) = 2NO(g) + Cl2(g) K = 1.56 x 10-5 If 2.00 moles of pure nitrogen monoxide and 3.00 moles of pure chlorine gas are placed in a 2.00-L container, calculate the concentration of Cl2(g) once the reaction has reached equilibrium.
N2(g) and O2(g) can exist in equilibrium with NO(g), as shown below. The equilibrium constant at 25.0°C is 4.8 x 10^-31. If initially there are 1.25 mol of nitrogen and 0.50 mol of oxygen in a 2.00 L vessel, find the equilibrium concentrations of each species.
Consider the reaction. PCI, (g) = PCI, (g) + Cl,(g) K. = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.140 M and [Cl2] = 0.170 M. What is the concentration of the reactant, PCI5 , at equilibrium? [PC!5] = M
Consider the following reaction where K. = 1.29x102 at 600 K. COCl»(g) eCO(g) + Cl2(g) A reaction mixture was found to contain 0.107 moles of COCI,(g), 2.44x102 moles of CO(g), and 4.39×102 moles of Cl2(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc, equals The reaction A. must run in the forward direction to reach equilibrium. B. must run in the reverse direction to reach equilibrium. C. is at equilibrium.
Consider the following equilibrium with K = 2.3 x 10-6: N2 ) + 3H2 (g) 2NH3 (g) 0.1 moles of N2, 0.1 moles of H2, and 0.01 moles of NH3 are placed in a 1 L container. Which of the following is true? O Q > K, the reaction will produce more products O Q = K, the reaction is at equilibrium O Q K, the reaction will produce more reactants
A sample of HI was placed in a container and the following reaction was allowed to come equilibrium. H₂(g) + 1₂(g) = 2 HI(g) The equilibrium concentrations were found to be [HI] = 3.88 M and [H₂] = [1₂] = 0.556. Calculate the equilibrium const Kc, for the reaction. Note Kc is often called K.
Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 3.0 L reaction vessel contained a mixture of 1.37 x 10-2 M HI, 6.47 × 10-3 M H2, and 5.94 × 10-4 M I, at 740 K. What are the values of Kc and Kp for the reaction at this temperature? H2(g) + 12(g) = 2 HI(g) 1 NEXT > Based on the given data, set up the expression for Kc and then evaluate it. Do not combine or simplify terms. K. = 2 RESET [1.37 x 10-2] [6.47 x 10-3] [5.94 × 10-4] [4.57 × 10-3] [2.16 х 10-3] [2.31 x 10-4] 2[1.37 x 10-2] 2[6.47 x 10-3] 2[5.94 x 10-4] [1.37 х 10-7)2 [6.47 x 10-312 [5.94 x 10-4]2 3.56 x 103 2.81 × 10-4 48.8 2.05 x 10-2
Consider the following reaction at a certain temperature: 4 Fe(s) + 3 O2(g)→ 2 Fe203(s) An equilibrium mixture contains 1.2 mol Fe, 0.00090 mol O2, and 2.0 mol Fez03 all in a 2.0-L container. Calculate the value of K for this reaction. K =
Consider the equilibrium between SbCl5, SbCl3 and Cl₂. SbCl5(g) SbCl3(g) + Cl₂(g) K = 2.46x10-² at 530 K The reaction is allowed to reach equilibrium in a 7.30-L flask. At equilibrium, [SbCl5] = 0.430 M, [SbCl3] = 0.103 M and [Cl₂] = 0.103 M. (a) The equilibrium mixture is transferred to a 14.6-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 14.6-L flask. [SbCl5] = [SbCl3] = [Cl₂] |||| ΣΣΣ
1. Consider the following reaction at 500 K: 2 NO (g) + O2 (g) 2 2 NO2 (g); Kc = 6.9 x 105 This reaction is allowed to reach equilibrium, and then analyzed and found to contain the following concentrations: [O2] = 1.0 x 10-3 M [NO2] = 5.0 x 10-2 M. Determine the equilibrium concentration of NO (g).