[References] (a) Use Hess's Law to calculate the enthalpy change for recovering tungston from its oxide using the reaction: WO3 (s) + 3 H₂ (9)→ W (s) + 3 H₂O (g) from the following data: 2 W (s)+3 0₂ (g)-2 WO3 (s) AH = -1627.8 kJ "Note: Should have 1 digit after the decimal AH=-222.86 kJ "Note: Should have 2 digits after the decimal 2 H₂ (g) + O₂ (g) - 2 H₂O (g) Answer 479.61 kJ D (b) Calculate the enthalpy change for the reaction: from the following data: NO (g) + 03 (9) NO₂ (g) + O₂(g) AH = -384.4 kJ 03 (9) - 3/2 0₂ (9) ΔΗ = 464.1 kJ 0₂ (9) 20 (g) AH = 739.6 kJ Note: All AHs above for part b should have 1 digit after the decimal Answer: Submit Answer NO (g) +0 (g) NO₂ (g) KJ Try Another Version 1 item attempt remaining Previous Next
[References] (a) Use Hess's Law to calculate the enthalpy change for recovering tungston from its oxide using the reaction: WO3 (s) + 3 H₂ (9)→ W (s) + 3 H₂O (g) from the following data: 2 W (s)+3 0₂ (g)-2 WO3 (s) AH = -1627.8 kJ "Note: Should have 1 digit after the decimal AH=-222.86 kJ "Note: Should have 2 digits after the decimal 2 H₂ (g) + O₂ (g) - 2 H₂O (g) Answer 479.61 kJ D (b) Calculate the enthalpy change for the reaction: from the following data: NO (g) + 03 (9) NO₂ (g) + O₂(g) AH = -384.4 kJ 03 (9) - 3/2 0₂ (9) ΔΗ = 464.1 kJ 0₂ (9) 20 (g) AH = 739.6 kJ Note: All AHs above for part b should have 1 digit after the decimal Answer: Submit Answer NO (g) +0 (g) NO₂ (g) KJ Try Another Version 1 item attempt remaining Previous Next
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
G.93.
![[References]
(a) Use Hess's Law to calculate the enthalpy change for recovering tungston from its oxide using the reaction:
WO3 (s) + 3 H₂ (9)→ W (s) + 3 H₂O (g)
from the following data
2 W (s)+3 0₂ (g)-2 WO3 (s) AH=-1627.8 kJ "Note: Should have 1 digit after the decimal
2 H₂ (g) + O₂(g) → 2 H₂O (g)
Answer 479.61 kJ
D
(b) Calculate the enthalpy change for the reaction:
from the following data:
Answer
AH = -222.86 kJ "Note: Should have 2 digits after the decimal
NO (g) + 03 (9) NO₂ (g) + O₂(g) AH = -384.4 kJ
03 (9)-3/2 02 (9)
O₂ (g) 20 (g) AH = 739.6 kJ
Note: All AHS above for part b should have 1 digit after the decimal
Submit Answer
kJ
AH = -464.1 kJ
NO (g) + O (g) → NO₂ (g)
Try Another Version
1 item attempt remaining
(Previous Next>](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbfa3ac40-09c9-4fe6-a042-1da4cda55b86%2F1e177a21-cbbb-4a67-8c03-b43169af0c3c%2Floexo7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[References]
(a) Use Hess's Law to calculate the enthalpy change for recovering tungston from its oxide using the reaction:
WO3 (s) + 3 H₂ (9)→ W (s) + 3 H₂O (g)
from the following data
2 W (s)+3 0₂ (g)-2 WO3 (s) AH=-1627.8 kJ "Note: Should have 1 digit after the decimal
2 H₂ (g) + O₂(g) → 2 H₂O (g)
Answer 479.61 kJ
D
(b) Calculate the enthalpy change for the reaction:
from the following data:
Answer
AH = -222.86 kJ "Note: Should have 2 digits after the decimal
NO (g) + 03 (9) NO₂ (g) + O₂(g) AH = -384.4 kJ
03 (9)-3/2 02 (9)
O₂ (g) 20 (g) AH = 739.6 kJ
Note: All AHS above for part b should have 1 digit after the decimal
Submit Answer
kJ
AH = -464.1 kJ
NO (g) + O (g) → NO₂ (g)
Try Another Version
1 item attempt remaining
(Previous Next>
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