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Refer to these values from the previous step. N = 15, M = 9, n = 6, k = 6, N-M= 6, n-k = 0 Substitute these values into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. N-M P(x = k) = P(x = 6) = Ck Cn-k MC N Cn C6 Co 15 Therefore, the probability of selecting six brown M&Ms from a candy dish containing nine brown and six red M&Ms is

Refer to these values from the previous step. N = 15, M = 9, n = 6, k = 6, N-M= 6, n-k = 0 Substitute these values into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. N-M P(x = k) = P(x = 6) = Ck Cn-k MC N Cn C6 Co 15 Therefore, the probability of selecting six brown M&Ms from a candy dish containing nine brown and six red M&Ms is

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 4 Refer to the values we have previously determined, N = 15, M = 9, n = 6, and k = 6. The remaining values needed for the formula are N - M and n - k. Find N - M. NM = 15 - 9 = 6 Find n - k. n-k= 6 - 6 = 0 Step 5 Refer to these values from the previous step. N = 15, M = 9, n = 6, k = 6, N - M = 6, n k = 0 Substitute these values into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. N - M P(x = k) P(x = 6) = = 6 M CKCn-k Cn C6⁹C06 C6² 15 N Therefore, the probability of selecting six brown M&Ms from a candy dish containing nine brown and six red M&Ms is
Transcribed Image Text:Step 4 Refer to the values we have previously determined, N = 15, M = 9, n = 6, and k = 6. The remaining values needed for the formula are N - M and n - k. Find N - M. NM = 15 - 9 = 6 Find n - k. n-k= 6 - 6 = 0 Step 5 Refer to these values from the previous step. N = 15, M = 9, n = 6, k = 6, N - M = 6, n k = 0 Substitute these values into the hypergeometric probability formula, or use technology. Round your final answer to four decimal places. N - M P(x = k) P(x = 6) = = 6 M CKCn-k Cn C6⁹C06 C6² 15 N Therefore, the probability of selecting six brown M&Ms from a candy dish containing nine brown and six red M&Ms is
Tutorial Exercise A candy dish contains nine brown and six red M&Ms. A child selects six M&Ms without checking the colors. What is the probability that all the M&Ms are brown? Step 1 First, we need to make sure the hypergeometric distribution is appropriate for this sample. We check that 0.05, where n = 6 is the number of M&Ms being selected, and N answer to two decimal places.) N 6 15 n N = = 0.4 n The ratio is N 0.40 Ch P(x = k) is greater than 0.05, so we can = Step 2 Recall that a hypergeometric distribution population contains M successes and N M failures. Consider drawing a brown M&M to be a success and a red M&M to be a failure. Given a total of nine brown and six red M&Ms in the dish, the total number of M&Ms was found in the previous step to be N = 15, and the total successes (or brown M&Ms) is M = 9 Step 3 Refer to the formula below for the probability of exactly k successes in a random sample of size n. СкМСп-к cn C N can use the hypergeometric probability distribution for this calculation. N - M - = 15 is the total number of M&Ms in the bowl. (Round your 6 With nine brown M&Ms in a bowl of fifteen M&Ms, we know M = 9 and N = 15. The remaining variables are the sample size n and the number of successes k. We know that six M&Ms are drawn, and we are calculating the probability of having exactly six brown M&Ms in that sample. Thus, in the sample of size n = 6 6 the number of successes, or brown M&Ms, is k = 6 I 9
Transcribed Image Text:Tutorial Exercise A candy dish contains nine brown and six red M&Ms. A child selects six M&Ms without checking the colors. What is the probability that all the M&Ms are brown? Step 1 First, we need to make sure the hypergeometric distribution is appropriate for this sample. We check that 0.05, where n = 6 is the number of M&Ms being selected, and N answer to two decimal places.) N 6 15 n N = = 0.4 n The ratio is N 0.40 Ch P(x = k) is greater than 0.05, so we can = Step 2 Recall that a hypergeometric distribution population contains M successes and N M failures. Consider drawing a brown M&M to be a success and a red M&M to be a failure. Given a total of nine brown and six red M&Ms in the dish, the total number of M&Ms was found in the previous step to be N = 15, and the total successes (or brown M&Ms) is M = 9 Step 3 Refer to the formula below for the probability of exactly k successes in a random sample of size n. СкМСп-к cn C N can use the hypergeometric probability distribution for this calculation. N - M - = 15 is the total number of M&Ms in the bowl. (Round your 6 With nine brown M&Ms in a bowl of fifteen M&Ms, we know M = 9 and N = 15. The remaining variables are the sample size n and the number of successes k. We know that six M&Ms are drawn, and we are calculating the probability of having exactly six brown M&Ms in that sample. Thus, in the sample of size n = 6 6 the number of successes, or brown M&Ms, is k = 6 I 9
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