Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​ (c) below.   TInterval ​(13.046,22.15) x overbar equals 17.598 Sxequals 16.01712719 nequals 50 a. Express the confidence interval in the format that uses the​ "less than" symbol. Given that the original listed data use one decimal​ place, round the confidence interval limits accordingly.   nothing   Mbpsless than muless thannothing   Mbps ​(Round to two decimal places as​ needed.) b. Identify the best point estimate of mu   and the margin of error.   The point estimate of mu   is nothing   Mbps. ​(Round to two decimal places as​ needed.) The margin of error is Eequals nothing   Mbps. ​(Round to two decimal places as​ needed.) c. In constructing the confidence interval estimate of mu ​, why is it not necessary to confirm that the sample data appear to be from a population with a normal​ distribution?     A. Because the sample is a random​ sample, the distribution of sample means can be treated as a normal distribution.   B. Because the sample size of 50 is greater than​ 30, the distribution of sample means can be treated as a normal distribution.   C. Because the population standard deviation is​ known, the normal distribution can be used to construct the confidence interval.   D. Because the sample standard deviation is​ known, the normal distribution can be used to construct the confidence interval

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​ (c) below.
 
TInterval
​(13.046,22.15)
x overbar

equals

17.598
Sxequals
16.01712719
nequals
50
a. Express the confidence interval in the format that uses the​ "less than" symbol. Given that the original listed data use one decimal​ place, round the confidence interval limits accordingly.
 
nothing
 
Mbpsless than

muless thannothing

 
Mbps
​(Round to two decimal places as​ needed.)
b. Identify the best point estimate of
mu
 
and the margin of error.
 
The point estimate of
mu
 

is

nothing
 
Mbps.
​(Round to two decimal places as​ needed.)
The margin of error is
Eequals

nothing

 
Mbps.
​(Round to two decimal places as​ needed.)
c. In constructing the confidence interval estimate of
mu
​,
why is it not necessary to confirm that the sample data appear to be from a population with a normal​ distribution?
 
 
A.
Because the sample is a random​ sample, the distribution of sample means can be treated as a normal distribution.
 
B.
Because the sample size of 50 is greater than​ 30, the distribution of sample means can be treated as a normal distribution.
 
C.
Because the population standard deviation is​ known, the normal distribution can be used to construct the confidence interval.
 
D.
Because the sample standard deviation is​ known, the normal distribution can be used to construct the confidence interval
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