1) Refer to table 1: What happens to the electrostatic forcebetween the two charges increases from 2 cm to 7 cm.FE as the distance r Electrostatic ForceCoulomb's LawNote: Position the first charge at 0 cm, then change the positions of the secondcharge to obtain the given distances in the tables below. Express the electrostatic forcein decimal notation. The first and last rows in each table are done for you.Table 1: Electrostatic Force (FE) vs Distance (r) between the two charges.ChargeChargeDistanceElectrostatic Force9192FE-4 µC8 µC2 cm719.004 N-4 µC8 µC3 cm8 με-4 µC4 cm- 4 µC8 µC5 cm-4 µC8 µC6 cm-4 µC8 µC7 cm- 4 µC8 μC8 cm44.938 N

The expression for the electrostatic force is given as, F=kq1q2r2

Answered: Refer to table 1: What happens to the…

Refer to table 1: What happens to the electrostatic force between the two charges increases from 2 cm to 7 cm. FE as the distance r

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1) Refer to table 1: What happens to the electrostatic force
between the two charges increases from 2 cm to 7 cm.
FE as the distance r

Electrostatic Force
Coulomb's Law
Note: Position the first charge at 0 cm, then change the positions of the second
charge to obtain the given distances in the tables below. Express the electrostatic force
in decimal notation. The first and last rows in each table are done for you.
Table 1: Electrostatic Force (
FE) vs Distance (r) between the two charges.
Charge
Charge
Distance
Electrostatic Force
91
92
FE
-4 µC
8 µC
2 cm
719.004 N
-4 µC
8 µC
3 cm
8 με
-4 µC
4 cm
- 4 µC
8 µC
5 cm
-4 µC
8 µC
6 cm
-4 µC
8 µC
7 cm
- 4 µC
8 μC
8 cm
44.938 N

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