Refer to Exhibit 13-31. The null hypothesis for this ANOVA problem is μ1 = μ₂ μ1 = μ2= μ3 О M1 = М2=M3 = M4 μ1 = μ₂=. = μ12
Refer to Exhibit 13-31. The null hypothesis for this ANOVA problem is μ1 = μ₂ μ1 = μ2= μ3 О M1 = М2=M3 = M4 μ1 = μ₂=. = μ12
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Transcribed Image Text:**Exhibit 13-31**
To test whether or not there is a difference between treatments A, B, C, and D, a sample of 12 observations has been randomly assigned to the four treatments. You are given the results below.
| Treatment | Observation |
|-----------|-----------------|
| A | 30, 25, 33 |
| B | 26, 20, 28 |
| C | 30, 28, 22 |
| D | 26, 34, 28 |
Refer to Exhibit 13-31. The null hypothesis for this ANOVA problem is _____.
- ☐ \( \mu_1 = \mu_2 \)
- ☐ \( \mu_1 = \mu_2 = \mu_3 \)
- ☐ \( \mu_1 = \mu_2 = \mu_3 = \mu_4 \)
- ☐ \( \mu_1 = \mu_2 = \ldots = \mu_{12} \)
**Explanation:**
This exhibit represents data for an Analysis of Variance (ANOVA) test. Four treatments (A, B, C, D) have been applied, each with three observations. The goal of the ANOVA test is to determine if there are any statistically significant differences between the means of these treatments. The null hypothesis states that all treatment means are equal. Hence, the correct null hypothesis is represented by the option \( \mu_1 = \mu_2 = \mu_3 = \mu_4 \).
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