Refer to diagram 3. An "infinite" wire lies along the x-axis carrying current /1 = 512 A in the +x-direction. A rectangular loop of wire (length a = 74.4 cm, width b = 54.9 cm) lies in the x-y plane and carries current /2 = 854 A counter-clockwise. Loop side a is parallel to the x-axis and distance d = 3.72 cm from it. Find F, the net force in N, exerted by the wire on the current loop. The sign will indicate if F is in the positive or the negative y-direction.

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Diagram 3
b
Q. x
Transcribed Image Text:Diagram 3 b Q. x
Refer to diagram 3.
An "infinite" wire lies along the x-axis carrying current /1 = 512 A in the +x-direction. A rectangular loop
of wire (length a = 74.4 cm, width b = 54.9 cm) lies in the x-y plane and carries current /2 = 854 A
counter-clockwise. Loop side a is parallel to the x-axis and distance d = 3.72 cm from it.
Find F, the net force in N, exerted by the wire on the current loop. The sign will indicate if F is in the
positive or the negative y-direction.
Transcribed Image Text:Refer to diagram 3. An "infinite" wire lies along the x-axis carrying current /1 = 512 A in the +x-direction. A rectangular loop of wire (length a = 74.4 cm, width b = 54.9 cm) lies in the x-y plane and carries current /2 = 854 A counter-clockwise. Loop side a is parallel to the x-axis and distance d = 3.72 cm from it. Find F, the net force in N, exerted by the wire on the current loop. The sign will indicate if F is in the positive or the negative y-direction.
Expert Solution
Step 1

Force on a current carrying conductor in magnetic field:

A current carrying conductor produces a magnetic field around it. It behaves like a magnet exerts a force when a magnet is placed in its magnetic field. A magnet also exerts equal and opposite force in the conductor.

Direction of this force is determined using Flemings left hand rule.

When a current element is placed in a magnetic field B, it experiences a force

                                                        dF =I dl ×B

 

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