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Refer to diagram 2. In the diagram: C, = 8.71 µF, C2 = 5.22 µF, C3 = 2.15 µF, C4 = 8.78 µF and V = 6.96 V. Initially, the switch is open and all the capacitors are neutral. After the switch is closed: find q3, the charge on C2 in µC.

Refer to diagram 2. In the diagram: C, = 8.71 µF, C2 = 5.22 µF, C3 = 2.15 µF, C4 = 8.78 µF and V = 6.96 V. Initially, the switch is open and all the capacitors are neutral. After the switch is closed: find q3, the charge on C2 in µC.

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**Diagram 2: Electrical Circuit with Capacitors** **Description:** This diagram illustrates an electrical circuit containing a voltage source, denoted by \( V \), and a series of capacitors arranged in both series and parallel configurations. The circuit includes a switch, labeled \( S \), which can open or close the circuit. **Components:** 1. **Voltage Source (\( V \))**: Provides the electric potential difference in the circuit and drives the current through connected components. 2. **Switch (\( S \))**: Allows the circuit to be completed or interrupted. When closed, current flows through the circuit; when open, the current ceases. 3. **Capacitors \( C_1, C_2, C_3, \) and \( C_4 \)**: - \( C_1 \) and \( C_2 \) are connected in series, meaning the charge on each capacitor is the same, and the total voltage across them is the sum of their individual voltages. - \( C_3 \) and \( C_4 \) are connected in parallel with each other and the series combination of \( C_1 \) and \( C_2 \). In parallel, the voltage across each capacitor is the same, and the total charge is the sum of the charges on each capacitor. **Functionality:** This configuration is used to study the different behaviors of capacitors in series and parallel connections. When the switch \( S \) is closed, the circuit is complete, allowing charge to accumulate on the capacitors, leading to different voltage distributions depending on individual capacitances and their arrangements. Understanding such configurations is fundamental in electronics, where capacitors are used for filtering, timing applications, and energy storage.
Transcribed Image Text:**Diagram 2: Electrical Circuit with Capacitors** **Description:** This diagram illustrates an electrical circuit containing a voltage source, denoted by \( V \), and a series of capacitors arranged in both series and parallel configurations. The circuit includes a switch, labeled \( S \), which can open or close the circuit. **Components:** 1. **Voltage Source (\( V \))**: Provides the electric potential difference in the circuit and drives the current through connected components. 2. **Switch (\( S \))**: Allows the circuit to be completed or interrupted. When closed, current flows through the circuit; when open, the current ceases. 3. **Capacitors \( C_1, C_2, C_3, \) and \( C_4 \)**: - \( C_1 \) and \( C_2 \) are connected in series, meaning the charge on each capacitor is the same, and the total voltage across them is the sum of their individual voltages. - \( C_3 \) and \( C_4 \) are connected in parallel with each other and the series combination of \( C_1 \) and \( C_2 \). In parallel, the voltage across each capacitor is the same, and the total charge is the sum of the charges on each capacitor. **Functionality:** This configuration is used to study the different behaviors of capacitors in series and parallel connections. When the switch \( S \) is closed, the circuit is complete, allowing charge to accumulate on the capacitors, leading to different voltage distributions depending on individual capacitances and their arrangements. Understanding such configurations is fundamental in electronics, where capacitors are used for filtering, timing applications, and energy storage.
**Problem Statement:** Refer to Diagram 2. In the diagram: - \( C_1 = 8.71 \, \mu\text{F} \) - \( C_2 = 5.22 \, \mu\text{F} \) - \( C_3 = 2.15 \, \mu\text{F} \) - \( C_4 = 8.78 \, \mu\text{F} \) The voltage \( V = 6.96 \, \text{V} \). Initially, the switch is open and all the capacitors are neutral. After the switch is closed, find \( q_3 \), the charge on \( C_2 \) in \( \mu\text{C} \). **Note:** Further explanation on diagrams and their arrangements would be useful for solving this problem; such analysis is dependent on how these capacitors are connected (e.g., series, parallel). Without a visual representation, it's assumed they are arranged in a manner typical for such problems.
Transcribed Image Text:**Problem Statement:** Refer to Diagram 2. In the diagram: - \( C_1 = 8.71 \, \mu\text{F} \) - \( C_2 = 5.22 \, \mu\text{F} \) - \( C_3 = 2.15 \, \mu\text{F} \) - \( C_4 = 8.78 \, \mu\text{F} \) The voltage \( V = 6.96 \, \text{V} \). Initially, the switch is open and all the capacitors are neutral. After the switch is closed, find \( q_3 \), the charge on \( C_2 \) in \( \mu\text{C} \). **Note:** Further explanation on diagrams and their arrangements would be useful for solving this problem; such analysis is dependent on how these capacitors are connected (e.g., series, parallel). Without a visual representation, it's assumed they are arranged in a manner typical for such problems.
Expert Solution
Step 1

Capacitor C3 and C4 are in parallel, so the equivalent capacitance is

C34=2.15 μF+8.78 μF=10.93 μF

C34 and C2 are in parallel, so the equivalent capacitance is

C234=5.22 μF10.93 μF5.22 μF+10.93 μF=3.5328 μF

 

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