ree then On) Given a binary tree, how do you connect all the adjacent nodes at the same level? Assume that Problem-88 given binary tree has next pointer along with left and right pointers as shown below.
ree then On) Given a binary tree, how do you connect all the adjacent nodes at the same level? Assume that Problem-88 given binary tree has next pointer along with left and right pointers as shown below.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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My professor has given me this assignment to make this
Handwritten answer is also acceptable ,but the algorithm should be correct. Do not give me incorrect answer . I will rate you negativity. Give me the optimal algorithm fast.
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Transcribed Image Text:nextLevelNodeCount %3;
prev = NULL;
Transcribed Image Text:Given a binary tree, how do you connect all the adjacent nodes at the same level? Assume that
is an AVL tree then O(n) is
Problem-88
given binary tree has next pointer along with left and right pointers as shown below.
struct BinaryTreeNode {
int data;
struct BinaryTreeNode *left;
struct BinaryTreeNode *right3;
struct BinaryTreeNode *next;
}3B
One simple approach is to use level-order traversal and keep updating the next pointers. While
traversing, we will link the nodes on the next level. If the node has left and right node, we will link left to right te
node has next node, then link rightmost child of current node to leftmost child of next node.
void linkingNodesOfSameLevel(struct BinaryTreeNode *root}{
struct Queue *Q = CreateQueue();
struct BinaryTreeNode *prev;
struct BinaryTreeNode *temp;
int currentLevelNodeCount, nextLevelNodeCount;
if(Iroot)
%3D
// Pointer to the previous node of the current level
return;
EnQueue(Q, root);
currentLevelNodeCount = 13;
nextLevelNodeCount = 0;
prev = NULL;
while (!IsEmptyQueue(Q)) {
temp = DeQueue(Q);
if (temp-left){
EnQueue(Q, temp-left);
nextLevelNodeCount++;
}
if (temp-right){
EnQueue(Q, temp-right);
nextLevelNodeCount++;
%3D
%3D
%3D
%3D
// Link the previous node of the current level to this node
if (prev)
prev--next = temp3;
// Set the previous node to the current
prev = temp;
currentLevelNodeCount--;
if (currentLevelNodeCount == 0) { // if this is the last node of the current level
currentLevelNodeCount = nextLevelNodeCount;
%3D
%3D
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