x = 0; for (i=1; i<=n; ii*3) { print("...") if (x > 0) { } print("...") for (j=1; √√j<=n; j++) { print("...") } for (k=2; k

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Compute the big O time complexity (worst case) of the code. Show all
work, including a table of steps to n, and then
all the summations and work to compute the time complexity

x = 0;
for (i=1; i<=n; ii*3) {
print("...")
if (x > 0) {
}
print("...")
for (j=1; √√j<=n; j++) {
print("...")
}
for (k=2; k<n; k=k²) {
print("...")
}
print("...")
x++;
}
Transcribed Image Text:x = 0; for (i=1; i<=n; ii*3) { print("...") if (x > 0) { } print("...") for (j=1; √√j<=n; j++) { print("...") } for (k=2; k<n; k=k²) { print("...") } print("...") x++; }
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