The recurrence relation is given as: a, = 04 an-1 - 4 an-2The initial conditions are given as: ao =1, a1 =4 and a2 = 12, .When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:Seç.Seç.Use a calculator and calculate ag2-2 and 1-0.5 and 22 and -2When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:-212464112641 and 116368

Answered: Image /qna-images/answer/6184999b-836f-4bd1-b4e3-32ebf7dc5a12.jpg

- recurrence relation is given as: a, = 04 an-1 - 4 an-2 - initial conditions are given as: ao =1, a1 =4 and a2 = 12, .. en you solve the characteristic equation, the root/roots of the characteristic equation can be found as: Seç. Seç. e a calculator and calculate ag -2 and 1 -0.5 and 2 2 and -2 en you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: -2 12464 11264 1 and 1

- recurrence relation is given as: a, = 04 an-1 - 4 an-2 - initial conditions are given as: ao =1, a1 =4 and a2 = 12, .. en you solve the characteristic equation, the root/roots of the characteristic equation can be found as: Seç. Seç. e a calculator and calculate ag -2 and 1 -0.5 and 2 2 and -2 en you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: -2 12464 11264 1 and 1

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

The recurrence relation is given as: a, = 04 an-1 - 4 an-2
The initial conditions are given as: ao =1, a1 =4 and a2 = 12, .
When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
Seç.
Seç.
Use a calculator and calculate ag
2
-2 and 1
-0.5 and 2
2 and -2
When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:
-2
12464
11264
1 and 1
16368

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