Recall the following equation from homework 3 We know that y₁ = ½, find y2. Therefore y1 t²y" + 4ty' + 2y = 0 Yıʊ" + (2y1 + py1) v' = 0. 1 4 "+ (-1+2)=0 By letting u = v' u' + 2 u = 0 Using separation of variables ln|u| = −2ln|t|+c u = ct-2 and ន || Y₂ = C 12 12 +2
Recall the following equation from homework 3 We know that y₁ = ½, find y2. Therefore y1 t²y" + 4ty' + 2y = 0 Yıʊ" + (2y1 + py1) v' = 0. 1 4 "+ (-1+2)=0 By letting u = v' u' + 2 u = 0 Using separation of variables ln|u| = −2ln|t|+c u = ct-2 and ន || Y₂ = C 12 12 +2
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
Question
can you explain these steps
![Recall the following equation from homework 3
We know that y₁ = ½, find y2.
Therefore
y1
t²y" + 4ty' + 2y = 0
Yıʊ" + (2y1 + py1) v' = 0.
1
4
"+ (-1+2)=0
By letting u = v'
u' +
2
u = 0
Using separation of variables
ln|u| = −2ln|t|+c
u = ct-2
and
ន
||
Y₂ =
C
12
12
+2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeefd442-7c64-4a51-8ed1-c0196ac6a13e%2Fee266c0a-f517-4dbd-8199-f6ccb3991c5e%2Frp3jgm6_processed.png&w=3840&q=75)
Transcribed Image Text:Recall the following equation from homework 3
We know that y₁ = ½, find y2.
Therefore
y1
t²y" + 4ty' + 2y = 0
Yıʊ" + (2y1 + py1) v' = 0.
1
4
"+ (-1+2)=0
By letting u = v'
u' +
2
u = 0
Using separation of variables
ln|u| = −2ln|t|+c
u = ct-2
and
ន
||
Y₂ =
C
12
12
+2
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