Rearrange the equation to solve for m. m = When a substance with a specific heat of 0.180 J/g C is heated from 26.2 °C to 78.6 °C, it absorbs 406 J of heat. Calculate the mass of the substance. m =

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Chapter1: Chemical Foundations
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The specific heat of a substance is the amount of heat required to raise the temperature of one gram of the substance by one
degree Celsius. The relationship between the amount of heat gained or released by a substance and the change in temperature of
the substance is given by the equation
q = MSAT
where q is the heat gained or released, m is the mass of the substance, s is the specific heat of the substance, and AT is the
change in temperature.
Rearrange the equation to solve for m.
m =
When a substance with a specific heat of 0.180 J/g ° C is heated from 26.2 °C to 78.6 °C, it absorbs 406 J of heat. Calculate the
mass of the substance.
m =
Transcribed Image Text:The specific heat of a substance is the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. The relationship between the amount of heat gained or released by a substance and the change in temperature of the substance is given by the equation q = MSAT where q is the heat gained or released, m is the mass of the substance, s is the specific heat of the substance, and AT is the change in temperature. Rearrange the equation to solve for m. m = When a substance with a specific heat of 0.180 J/g ° C is heated from 26.2 °C to 78.6 °C, it absorbs 406 J of heat. Calculate the mass of the substance. m =
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