Reading proficiency: An educator wants to construct a 98% confidence interval for the proportion of elementary school children in Colorado who are proficientin reading.Part: 0/ 3Part 1 of 3(a) The results of a recent statewide test suggested that the proportion is 0.75. Using this estimate, what sample size is needed so that the confidenceinterval will have a margin of error of 0.04?A sample ofelementary school children is needed to obtain a 98% confidence interval with a margin of error of 0.04.NOVMacBook Air吕0DIIDDF2F3F4FSF6F7F8F10@%23$%&346

Given Pcap=0.75 1-pcap=0.25 Margin of error (n) =4%=0.04

Answered: Reading proficiency: An educator wants…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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How to calculate a 90% confidence interval?
According to a poll, 79% of California adults (398 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.) Additional Materials Reading
We have conducted a one sided hypothesis test with a significance level a = 0.05. We would like to also construct a confidence interval with an equivalent level so that we can compare our results. What should the confidence level of this interval be? (Note: Do not include the percent sign.)
Next question If a sample proportion is 0.68, which of the following could be a 90% confidence interval for the population proportion? ..... Select all that apply. A. Lower bound: 0.59; Upper bound: 0.77 B. Lower bound: 0.66; Upper bound: 0.70 OC. Lower bound: 0.50; Upper bound: 0.77 D. Lower bound: 0.77; Upper bound: 0.95 E. Lower bound: 0.67; Upper bound: 0.71 F3 F4 F5 F7 F8 24 4. %23 2 3. 6. Left control option command
Early-childhood-development studies indicate that the more often a child is read to from birth, the earlier the child begins to read. A local parents’ group wants to test this theory and samples families with young children. They find the following results. Construct a 99% confidence interval to estimate the true difference between the proportions of children who read at an early age when they are read to frequently compared to those who were read to less often, as described in the table of results. Let Population 1 be the children who were read to frequently and Population 2 be the children who were read to less often. Round the endpoints of the interval to three decimal places, if necessary. Ages when Children Begin to Read Read to at Least Three Times per Week Read to Fewer than Three Times per Week Started Reading by age 4 60 35 Started Reading after age 4 36 51 Lower end point: Upper end point:
you conducted additional studies with these men and found the following: a. The RR for those who drank one drink per day was 1.50 (95% CI:1.32-1.67) in comparison to the abstainers. b. For those men who drank three or more drinks per day the RR compared to the abstainers was 4.20 (95% CI 2.68-5.85). Question: We can tell from the Confidence Intervals provided in #7 whether there are likely more people in the “one drink a day” group or the “3+ drinks per day” group. Which one likely has more people and how can we tell?
Surgical complications: A medical researcher wants to construct a 99.8% confidence interval for the proportion of knee replacement surgeries that result in complications. Part: 0 / 2 Part 1 of 2 (a) An article in a medical journal suggested that approximately 15% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.03? A sample of operations is needed to obtain a 99.8% confidence interval with a margin of error of 0.03 using the estimate 0.15 for p.
In a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1=not attractive; 10=extremely attractive). Construct a confidence interval using a 90% confidence level. What do the results tell about the mean attractiveness ratings of the population of all adult females? 5,7,2,9,4,4,6,9,7,8,6,8
in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.- I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)
You want to find a 92% confidence interval for the proportion of PLM students who get a student scholarship allowance from the government of the City of Manila. You found an information from the city administrator that states that around 75% of PLM students are to get the allowance. At a maximum error of 5%, how many samples do you need?
A 95% confidence interval implies that: A. We are 95% confident that the interval contains the true population mean B. The interval range contains 95% of the values in your dataset C. There is a 5% chance the mean will be found in the CI range

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