Reaction Force at Joint A? Reaction Force at Joint I? B 70° 1 45° D C 20 lbs 12.00- 36.62⁰ F E 30 lbs H G -3.02- J

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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What is the reaction at force joint A and I. What is the C and T, the X and Y components, the load and the length of each member. Also could you put the answer like it is on the image.
**Diagram Description**

- The diagram illustrates a truss structure with labeled joints and members.
- The structure is symmetrical horizontally and has a total span of 12.00 units across the top.
- The points A to J are marked, with angles at joints B (45°) and D (70°) on the left side as well as angles at joints D (36.62°) on the right side.
- Vertical loads are applied at point C (20 lbs downward) and point E (30 lbs downward).
- There is a horizontal distance of 3.02 units from joint G to joint I.
- Reaction forces are indicated at joint A (vertically upward) and joint I (vertically upward).

**Member Analysis Table**

| Member | C or T | X  | Y  | Load | Length |
|--------|--------|----|----|------|--------|
| AB     |        |    |    |      |        |
| AC     |        |    |    |      |        |
| BC     |        |    |    |      |        |
| BD     |        |    |    |      |        |
| CD     |        |    |    |      |        |
| CE     |        |    |    |      |        |
| DE     |        |    |    |      |        |
| DF     |        |    |    |      |        |
| FE     |        |    |    |      |        |
| FH     |        |    |    |      |        |
| EH     |        |    |    |      |        |
| EG     |        |    |    |      |        |
| HG     |        |    |    |      |        |
| HJ     |        |    |    |      |        |
| GJ     |        |    |    |      |        |
| GI     |        |    |    |      |        |
| JI     |        |    |    |      |        |

**Equation**

- \(2(j) = m + 3\)
  - \(j\) = joints
  - \(m\) = members

**Instructions**

- Solve the equation provided.
- Calculate reaction forces at joints A and I.
- Prepare a free body diagram for each joint.
- Show all calculations and round to two decimal places.

**Additional Information**

-
Transcribed Image Text:**Diagram Description** - The diagram illustrates a truss structure with labeled joints and members. - The structure is symmetrical horizontally and has a total span of 12.00 units across the top. - The points A to J are marked, with angles at joints B (45°) and D (70°) on the left side as well as angles at joints D (36.62°) on the right side. - Vertical loads are applied at point C (20 lbs downward) and point E (30 lbs downward). - There is a horizontal distance of 3.02 units from joint G to joint I. - Reaction forces are indicated at joint A (vertically upward) and joint I (vertically upward). **Member Analysis Table** | Member | C or T | X | Y | Load | Length | |--------|--------|----|----|------|--------| | AB | | | | | | | AC | | | | | | | BC | | | | | | | BD | | | | | | | CD | | | | | | | CE | | | | | | | DE | | | | | | | DF | | | | | | | FE | | | | | | | FH | | | | | | | EH | | | | | | | EG | | | | | | | HG | | | | | | | HJ | | | | | | | GJ | | | | | | | GI | | | | | | | JI | | | | | | **Equation** - \(2(j) = m + 3\) - \(j\) = joints - \(m\) = members **Instructions** - Solve the equation provided. - Calculate reaction forces at joints A and I. - Prepare a free body diagram for each joint. - Show all calculations and round to two decimal places. **Additional Information** -
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