Reaction Force at Joint A? Reaction Force at Joint I? B 70° 1 45° D C 20 lbs 12.00- 36.62⁰ F E 30 lbs H G -3.02- J
Reaction Force at Joint A? Reaction Force at Joint I? B 70° 1 45° D C 20 lbs 12.00- 36.62⁰ F E 30 lbs H G -3.02- J
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
What is the reaction at force joint A and I. What is the C and T, the X and Y components, the load and the length of each member. Also could you put the answer like it is on the image.

Transcribed Image Text:**Diagram Description**
- The diagram illustrates a truss structure with labeled joints and members.
- The structure is symmetrical horizontally and has a total span of 12.00 units across the top.
- The points A to J are marked, with angles at joints B (45°) and D (70°) on the left side as well as angles at joints D (36.62°) on the right side.
- Vertical loads are applied at point C (20 lbs downward) and point E (30 lbs downward).
- There is a horizontal distance of 3.02 units from joint G to joint I.
- Reaction forces are indicated at joint A (vertically upward) and joint I (vertically upward).
**Member Analysis Table**
| Member | C or T | X | Y | Load | Length |
|--------|--------|----|----|------|--------|
| AB | | | | | |
| AC | | | | | |
| BC | | | | | |
| BD | | | | | |
| CD | | | | | |
| CE | | | | | |
| DE | | | | | |
| DF | | | | | |
| FE | | | | | |
| FH | | | | | |
| EH | | | | | |
| EG | | | | | |
| HG | | | | | |
| HJ | | | | | |
| GJ | | | | | |
| GI | | | | | |
| JI | | | | | |
**Equation**
- \(2(j) = m + 3\)
- \(j\) = joints
- \(m\) = members
**Instructions**
- Solve the equation provided.
- Calculate reaction forces at joints A and I.
- Prepare a free body diagram for each joint.
- Show all calculations and round to two decimal places.
**Additional Information**
-
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